# Removing additional points from scatter plot

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Prasad Joshi on 11 Feb 2022
Commented: Prasad Joshi on 11 Feb 2022
How can I removed this additional legend data and keep only 2kw , 3kw and 4 kw and remove additional data points from legend of scatter plot ..Thank you in advance
The code That i used
i= 1
x1=ones(1,3);
y1=A(:,(i:(i+2)))
hold on
a=scatter(x1,y1,'filled','r')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x1(1),y1(1),sprintf(' (%.1f)[55 55]',y1(1)))
text(x1(2),y1(2),sprintf(' (%.1f)[55 35]',y1(2)))
text(x1(3),y1(3),sprintf(' (%.1f)[35 35]',y1(3)))
i= 4
x2=(ones(1,3)+1);
y2=A(:,(i:(i+2)))
hold on
scatter(x2,y2,'filled','r')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x2(1),y2(1),sprintf(' (%.1f)[55 55]',y2(1)))
text(x2(2),y2(2),sprintf(' (%.1f)[55 35]',y2(2)))
text(x2(3),y2(3),sprintf(' (%.1f)[35 35]',y2(3)))
i= 7
x3=(ones(1,3)+2);
y3=A(:,(i:(i+2)))
hold on
scatter(x3,y3,'filled','r')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x3(1),y3(1),sprintf(' (%.1f)[55 55]',y3(1)))
text(x3(2),y3(2),sprintf(' (%.1f)[55 35]',y3(2)))
text(x3(3),y3(3),sprintf(' (%.1f)[35 35]',y3(3)))
i= 10
x4=(ones(1,3));
y4=A(:,(i:(i+2)))
hold on
scatter(x4,y4,'filled','b')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x4(1),y4(1),sprintf(' (%.1f)[55 55]',y4(1)))
text(x4(2),y4(2),sprintf(' (%.1f)[55 35]',y4(2)))
text(x4(3),y4(3),sprintf(' (%.1f)[35 35]',y4(3)))
i= 13
x5=(ones(1,3)+1);
y5=A(:,(i:(i+2)))
hold on
scatter(x5,y5,'filled','b')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x5(1),y5(1),sprintf(' (%.1f)[55 55]',y5(1)))
text(x5(2),y5(2),sprintf(' (%.1f)[55 35]',y5(2)))
text(x5(3),y5(3),sprintf(' (%.1f)[35 35]',y5(3)))
i= 16
x6=(ones(1,3)+2);
y6=A(:,(i:(i+2)))
scatter(x6,y6,'filled','b')
hold on
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x6(1),y6(1),sprintf(' (%.1f)[55 55]',y6(1)))
text(x6(2),y6(2),sprintf(' (%.1f)[55 35]',y6(2)))
text(x6(3),y6(3),sprintf(' (%.1f)[35 35]',y6(3)))
i= 19
x7=(ones(1,3));
y7=A(:,(i:(i+2)))
hold on
scatter(x7,y7,'filled','k')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x7(1),y7(1),sprintf(' (%.1f)[55 55]',y7(1)))
text(x7(2),y7(2),sprintf(' (%.1f)[55 35]',y7(2)))
text(x7(3),y7(3),sprintf(' (%.1f)[35 35]',y7(3)))
i= 22
x8=(ones(1,3)+1);
y8=A(:,(i:(i+2)))
hold on
scatter(x8,y8,'filled','k')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x8(1),y8(1),sprintf(' (%.1f)[55 55]',y8(1)))
text(x8(2),y8(2),sprintf(' (%.1f)[55 35]',y8(2)))
text(x8(3),y8(3),sprintf(' (%.1f)[35 35]',y8(3)))
i= 25
x9=(ones(1,3)+2);
y9=A(:,(i:(i+2)))
hold on
scatter(x9,y9,'filled','k')
xtics=[0:1:4];
xticlab={'' '20sec' '35sec' '50sec' ''};
set(gca,'XTick',xtics,'XTickLabel',xticlab,'Fontsize', 10)
text(x9(1),y9(1),sprintf(' (%.1f)[55 55]',y9(1)))
text(x9(2),y9(2),sprintf(' (%.1f)[55 35]',y9(2)))
text(x9(3),y9(3),sprintf(' (%.1f)[35 35]',y9(3)))
xlim([0 4])
ylabel('CO emissions [mg]')
title ('CO emission for 25 sec after catalyst 1')
legend('2 kW' ,'' ,'' ,'3 kW' ,'','','4 kW')
Prasad Joshi on 11 Feb 2022
Actually I am not that much proficient in Programming a beginner .....I am just seeing from online stuffs and developing code ...can you suggest how can I add for loop to this case ...Thank you in advance

Prasad Joshi on 11 Feb 2022
Just in cases anyone requiried add duplicate entries to code ...it work for me
hold on
h1 = scatter(-10,-10, 'r,'filled', 'DisplayName', ' 2kW');
h2 = scatter(-10,-10, 'b','filled', 'DisplayName', '3 kW');
h3 = scatter(-10,-10, 'k','filled', 'DisplayName', '4 kW');
% duplicating the plot
xlim([0 10] ) % taking positive values
legend([h1(1) h2(1) h3(1)])
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Prasad Joshi on 11 Feb 2022
ya ...Thank you RIK for you help ......