I got two different graphs from my code like ODE89 and Eulers method. I need to compare the graphs in it.
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Naveen Krish
on 14 Mar 2022
Commented: Naveen Krish
on 18 Mar 2022
ODE89
clc
clear all
A0=1;
B0=3;
P0=0;
K=5*10^-5;
Yb=1;
Yp=0.15;
tspan = [0 43200];
[t,Y] = ode89(@(t,Y) odefun(t,Y, K, Yb, Yp),tspan, [A0;B0;P0]);
figure (1)
plot(t,Y(:,1))
figure (2)
plot(t,Y(:,2))
figure (3)
plot(t,Y(:,3))
function dYdt = odefun(t,Y,K,Yb,Yp)
dYdt = [(-K*Y(1)*Y(2));
(-Yb*(K*Y(1)*Y(2)));
(Yp*(K*Y(1)*Y(2)))];
end
Eulers
nsteps = 12;
t = zeros (nsteps,1);
A = zeros (nsteps,1);
B = zeros(nsteps, 1);
P = zeros(nsteps,1);
A(1) = 1;
B(1) = 3;
C(1) = 0;
K = 5*10^-5
for k = 2:13
t(k) = t(k-1)+3600
A(k) = A(k-1)+(-K*A(k-1)*B(k-1))*3600;
B(k) = B(k-1)+(-Yb*(K*A(k-1)*B(k-1)))*3600;
P(k)= P(k-1)+ Yp*(K*A(k-1)*B(k-1))*3600;
end
plot (t,A)
figure (1)
plot(t,A(:,1))
plot (t,B)
figure (2)
plot(t,B(:,1))
plot(t,P)
figure (3)
plot(t,P(:,1))
I need to compare the ODE89 graph of A,B and P with Euler's A,B and P
2 Comments
AndresVar
on 14 Mar 2022
They look pretty similar, so to make it easier to draw comparisons you can plot the corresponding solutions on the same axis.
Maybe you can plot the percent differce on the right-hand side axis also.
Accepted Answer
Davide Masiello
on 15 Mar 2022
Edited: Davide Masiello
on 15 Mar 2022
clc
clear all
%% ODE89
A0=1;
B0=3;
P0=0;
K=5*10^-5;
Yb=1;
Yp=0.15;
tspan = [0 43200];
[x,Y] = ode89(@(t,Y) odefun(t,Y, K, Yb, Yp),tspan, [A0;B0;P0]);
%% Euler
nsteps = 12;
t = zeros (nsteps,1);
A = zeros (nsteps,1);
B = zeros(nsteps, 1);
P = zeros(nsteps,1);
A(1) = 1;
B(1) = 3;
C(1) = 0;
K = 5*10^-5;
for k = 2:13
t(k) = t(k-1)+3600;
A(k) = A(k-1)+(-K*A(k-1)*B(k-1))*3600;
B(k) = B(k-1)+(-Yb*(K*A(k-1)*B(k-1)))*3600;
P(k)= P(k-1)+ Yp*(K*A(k-1)*B(k-1))*3600;
end
figure(1)
subplot(1,3,1)
plot (t,A,x,Y(:,1))
xlabel('t')
ylabel('A')
subplot(1,3,2)
plot (t,B,x,Y(:,2))
xlabel('t')
ylabel('B')
subplot(1,3,3)
plot(t,C,x,Y(:,3))
xlabel('t')
ylabel('P')
legend('ODE89','Euler','Location','Best')
function dYdt = odefun(t,Y,K,Yb,Yp)
dYdt = [(-K*Y(1)*Y(2));
(-Yb*(K*Y(1)*Y(2)));
(Yp*(K*Y(1)*Y(2)))];
end
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