find the point of intersection of one curve with itselfs
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hey Everyone,
i have:
x = [2 0 0 2 2 -1]';
y = [4 4 0 0 2 2]';
and i have to to find the point, where the function cuts itselfs. I know it should work with cscvn and anonymous function but i dont know how exactly. A picture of the function is attached
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Accepted Answer
Kevin Holly
on 16 Jun 2022
Edited: Kevin Holly
on 16 Jun 2022
x = [2 0 0 2 2 -1];
y = [4 4 0 0 2 2];
points = [x;y];
h=fnplt(cscvn(points));
plot(h(1,:),h(2,:));hold on,
plot(points(1,:),points(2,:),'o'), hold off
[yi,xi] = polyxpoly(h(2,1:round(end/2)-1),h(1,1:round(end/2)-1),h(2,round(end/2):end),h(1,round(end/2):end))
hold on
plot(xi,yi,'g*')
xi
yi
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