I want to rounding selected data with Looping and If else
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I have workspace variable "a" which there is a 510x1 matrix data inside like this
I want to change cell containing 10+ only (like 10.0299, 10.0419, 10.0064,.......) change to be 10.0000. And this is my program code and I use rounding function to make 10,+ data change to be 10.0000
n=length(a);
for i=1:n
if(a > 0 & a < 10)
v=(round(a,0))
else
v=a
end
end
After I run the program, there is no change on "a" data (still like that picture), and if I switch "v=(round(a,0))" and "v=a" position and run it, all data in matrix are rounded like 9.0000; 10,0000;....... what's wrong with my code? thank you
1 Comment
Stephen23
on 9 May 2023
" want to change cell containing 10+ only (like 10.0299, 10.0419, 10.0064,.......) change to be 10.0000"
The very simple and very efficient MATLAB approach:
a = min(10,a)
Any other code you can come up with will be slower and more complex than that.
Answers (2)
DGM
on 8 May 2023
Edited: DGM
on 8 May 2023
It's not really clear what the desired conditions are.
If what you want is to constrain values to the interval [0 10], you can do that like so:
A = [-1.2 1.2 8.5 12.5];
% using min(max())
B = min(max(A,0),10)
% or using imclamp() (attached)
B = imclamp(A,[0 10])
This keeps values inside the interval unchanged.
Both of these examples do the same thing. The only difference is that the latter is easier to read and less prone to mistakes.
If you only need a one-sided constraint, you can use min() by itself
0 Comments
VBBV
on 8 May 2023
Edited: VBBV
on 9 May 2023
a = rand(1)*randi([5 25],510,1)
n=length(a);
for i=1:n
if(a(i) > 0 & a(i) < 10)
a(i) = a(i);
else
a(i) = round(a(i),0);
end
end
a
Use the round function shown as above.
1 Comment
VBBV
on 8 May 2023
Also, when you use a directly in the if-else condition , it refers to all elements in the vector at once.
You need to access individual elements one by one and then round them
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