for generation of 10 i nput in each sequence for a sinusoidal signal

for k=4:1000

x(k) = 1.05 * sin(pi*k/45);

x(k-3:k+10-4)

end

In the above question, if I want to generate a input sequence in a batch of 10 for each iteration . Then how can we implement it?

Answer 1

[VBBV]

clearvars
% size or range of iteration 
k = 4:1000;
x = 1.05 * sin(pi*k/45)

x = 1×997

0.2894 0.3591 0.4271 0.4929 0.5564 0.6172 0.6749 0.7294 0.7803 0.8274 0.8705 0.9093 0.9437 0.9735 0.9986 1.0188 1.0340 1.0442 1.0494 1.0494 1.0442 1.0340 1.0188 0.9986 0.9735 0.9437 0.9093 0.8705 0.8274 0.7803

for J = 1:length(k)-9
   X(J,:) = x(J:J+9);
end
% batch of 10 inputs per iteration 
X

X = 988×10

0.2894 0.3591 0.4271 0.4929 0.5564 0.6172 0.6749 0.7294 0.7803 0.8274 0.3591 0.4271 0.4929 0.5564 0.6172 0.6749 0.7294 0.7803 0.8274 0.8705 0.4271 0.4929 0.5564 0.6172 0.6749 0.7294 0.7803 0.8274 0.8705 0.9093 0.4929 0.5564 0.6172 0.6749 0.7294 0.7803 0.8274 0.8705 0.9093 0.9437 0.5564 0.6172 0.6749 0.7294 0.7803 0.8274 0.8705 0.9093 0.9437 0.9735 0.6172 0.6749 0.7294 0.7803 0.8274 0.8705 0.9093 0.9437 0.9735 0.9986 0.6749 0.7294 0.7803 0.8274 0.8705 0.9093 0.9437 0.9735 0.9986 1.0188 0.7294 0.7803 0.8274 0.8705 0.9093 0.9437 0.9735 0.9986 1.0188 1.0340 0.7803 0.8274 0.8705 0.9093 0.9437 0.9735 0.9986 1.0188 1.0340 1.0442 0.8274 0.8705 0.9093 0.9437 0.9735 0.9986 1.0188 1.0340 1.0442 1.0494