Reduce Computing Time Part 2

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Dejan Cvijanovic
Dejan Cvijanovic on 30 Apr 2012
Original Q:
"Hey I have somewhat tricky task of reducing computation time for one line of code in my professor's project. Is there any way to reduce the following code so that it computes at a faster rate (maybe 0.01s), right now the time to beat is 0.08s. The code is as follows:
(32 bit IEEE demultiplexed)
x = hex2float( dec2hex( fread(fid, 1, 'ubit32', 0, 'ieee-be') )) Basicslly looking for quicker way to convert the binary file to float. If you're not sure, I'm open to specifics suggestions. Also, would it be better if I wrote a code like this in C first and then let matlab read from there? Thank you."
I have tried this code:
x = fread(fid, 1, 'ubit32=>float32', 0, 'ieee-be')
and got this response back from prof;
"Dejan,
It doesn't work, function provides totally different number. For testing I would suggest to create input "number" (file, or just this 32 something variable in line). To do so I would try reverse, say take some double, convert it to float then, float2hex, then hex2dec. As a result I assume that you would have variable to play with and apply different solutions for x to covvert it back.
-Y"
Any suggestions based off this? I'm still somewhat confused. Again, can't test directly as I don't have Matlab at home.
  7 Comments
Walter Roberson
Walter Roberson on 30 Apr 2012
No, ubit32 reads 32 bits, not 32 1-byte values.

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Answers (1)

Dejan Cvijanovic
Dejan Cvijanovic on 30 Apr 2012
Should it just be
x = fread(fid, 1, 'ubit32=>double', 0, 'ieee-be')
would that solve the problem?

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