An accumulating matrix to be reset when the limit value is reached, the value being reset must be moved to another matrix

2 views (last 30 days)
Hello
can someone please help me with this challenge.
matrix
B = [1, 4, 3, 1, 3, 2, 1, 0, 0, 1, 5, 6, 9, 1, 3]
A = cumsum (B);
A = [1, 5, 8, 9, 12, 14, 15, 15, 15, 16, 21, 27, 36, 37, 40]
Then i want A and C to act like this
A = [1, 0, 3, 4, 0, 2, 3, 3, 3, 4, 0, 0, 0, 1, 3] % Every time it exceds 5, the value has to be moved to C, and reset to 0
C = [0, 5, 0, 0, 7, 0, 0, 0, 0, 0, 9, 6, 9, 0, 0]
  3 Comments
Rune Kalhoej
Rune Kalhoej on 12 May 2019
primary loops, like this
clc
B = [5,3,4,7,8,6,3,2,1,0,3,2,7,8,3,4,2];
A = cumsum(B); %Dette er den matrice du vil sortere alt over 5
C = zeros(length(A),1); %Alle værdier over 5 fra Matrix matricen, bliver lagt over i denne, resten er 0.
for i = 1:length(A)
if A(i)>=5
C(i) = A(i);
A(i) = 0; % den skal samtidig nulstilles , virker ikke :S
else
C(i) = 0;
end
end
table(A',C)

Sign in to comment.

Accepted Answer

Rik
Rik on 12 May 2019
This should do the trick. Note that you should use numel to count the number of elements, not length, which is just doing max(size(A)). The difference is usually nothing, but it will trip you up at some point.
B = [1, 4, 3, 1, 3, 2, 1, 0, 0, 1, 5, 6, 9, 1, 3];
A = cumsum (B);
C = zeros(size(A));
idx=find(A>=5);
while ~isempty(idx)
idx=idx(1);
C(idx)=A(idx);
A(idx:end)=A(idx:end)-A(idx);
idx=find(A>=5);
end
FormatSpec=[repmat('%d, ',1,numel(A)) '\n'];FormatSpec(end-3)='';
clc
fprintf(FormatSpec,A)
fprintf(FormatSpec,C)
Alternatively (which might be faster in some cases):
B = [1, 4, 3, 1, 3, 2, 1, 0, 0, 1, 5, 6, 9, 1, 3];
A = cumsum (B);
C = zeros(size(A));
idx=find(A>=5);
while ~isempty(idx)
idx=idx(1);
C(idx)=A(idx);
A=A-A(idx);
idx=find(A>=5);
end
A=cumsum(B)-cumsum(C);%restore real A

More Answers (0)

Categories

Find more on Linear Algebra in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!