How can I find a vector in a matrix without using cycles?

1 view (last 30 days)
Good afternoon. The reason for my message is to ask for help with this problem. Let's say I have a matrix "called A" with 2 columns and -n- number of rows, and I need to look for a vector "B" (which is 1 row and 2 columns) within all the rows that make up "A". You must find the vector in a way that recognizes in a sense or in the opposite sense, then I show an example to better understand what I say.
A =
1 2
3 4
5 3
3 1
6 4
4 2
B=
4 6 -------------------> The vector B can also be inverted (6 4).
The result I expect to be told in which row is the vector "B" inside the matrix "A". for the example above I would expect the answer to be row 5
Thank you very much for your help.

Accepted Answer

Star Strider
Star Strider on 22 May 2019
Try this:
A = [1 2
3 4
5 3
3 1
6 4
4 2];
B = [4 6];
Lidx = ismember(sort(A,2),sort(B,2),'rows')
rowNumber = find(Lidx)
producing:
Lidx =
6×1 logical array
0
0
0
0
1
0
rowNumber =
5
  4 Comments
Pedro Guevara
Pedro Guevara on 22 May 2019
Works perfect companion, thank you very much for your huge help. :)

Sign in to comment.

More Answers (0)

Categories

Find more on MATLAB in Help Center and File Exchange

Products


Release

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!