Index exceeds matrix dimensions. where is mistake

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II=[14 23;44 15];
R=II(:)';
x=0.3;
p=0.343;
for n=2:4;
if x(n-1)>=0 & x(n-1)<=p
x(n)=x(n-1)/p;
else
x(n)=(1-x(n-1))/(1-p);
end
end
A=sort(x);
[A,T]=sort(x);
Y=R(T);
C=reshape(Y,[2,2]);
r = 3.8;
size = 4;
L(1)= 0.234;
for i=2:size
L(i) = r*L(i-1)*(1-L(i-1));
end
mm=min(L);
nn=max(L);
oo=nn-mm;
Z=uint8(8*((L-mm)/oo))+1;
%for i=1:9
%K(i)=mod((abs(L(i))-floor(abs(L(i))))*1e14,50);
%end
CC(1)=bitxor(mod(157,50),mod(Y(1)+Z(1),50));
for i=2:4
CC(i)=bitxor(mod(CC(i-1),50),mod(Y(i)+Z(i),50));
end
X=[12 13 13 14;12 15 16 34;17 18 19 13 ;12 34 32 31];
sX=size(X);
[cA,cH,cV,cD] = dwt2(X,'db4');
subplot(2,2,1);
imagesc(cA);
colormap gray;
title('Approximation');
subplot(2,2,2);
imagesc(cH);
colormap gray;
title('Horizontal');
subplot(2,2,3);
imagesc(cV);
colormap gray;
title('Vertical');
subplot(2,2,4);
imagesc(cD);
colormap gray;
title('Diagonal');
for m=1:2;
for n=1:2;
VV(m,n)=floor(C(m,n)/10);
DD(m,n)=mod(C(m,n),10);
end
end
S = idwt2(cA,cH,VV,DD,'db4',sX);

Answers (2)

Raj
Raj on 4 Jul 2019
In line number 17 you have defined
size = 4;
which you are using in your 'for' loop at line 19. This variable is clashing with Matlab inbuilt function 'size' which you are trying to use at line 34. Hence you are getting the error. Change the variable name.
  1 Comment
KALYAN ACHARJYA
KALYAN ACHARJYA on 4 Jul 2019
Edited: KALYAN ACHARJYA on 4 Jul 2019
Yes @Raj
Size variable name (line 7) is confliting with inbuilt function name.
II=[14 23;44 15];
R=II(:)';
x=0.3;
p=0.343;
for n=2:4;
if x(n-1)>=0 & x(n-1)<=p
x(n)=x(n-1)/p;
else
x(n)=(1-x(n-1))/(1-p);
end
end
A=sort(x);
[A,T]=sort(x);
Y=R(T);
C=reshape(Y,[2,2]);
r = 3.8;
size1 = 4; %%% Issue was here, I have change the variable name size to size1
L(1)= 0.234;
for i=2:size1
L(i) = r*L(i-1)*(1-L(i-1));
end
mm=min(L);
nn=max(L);
oo=nn-mm;
Z=uint8(8*((L-mm)/oo))+1;
%for i=1:9
%K(i)=mod((abs(L(i))-floor(abs(L(i))))*1e14,50);
%end
CC(1)=bitxor(mod(157,50),mod(Y(1)+Z(1),50));
for i=2:4
CC(i)=bitxor(mod(CC(i-1),50),mod(Y(i)+Z(i),50));
end
X=[12 13 13 14;12 15 16 34;17 18 19 13;12 34 32 31];
sX=size(X);
[cA,cH,cV,cD] = dwt2(X,'db4');
subplot(2,2,1);
imagesc(cA);
colormap gray;
title('Approximation');
subplot(2,2,2);
imagesc(cH);
colormap gray;
title('Horizontal');
subplot(2,2,3);
imagesc(cV);
colormap gray;
title('Vertical');
subplot(2,2,4);
imagesc(cD);
colormap gray;
title('Diagonal');
for m=1:2;
for n=1:2;
VV(m,n)=floor(C(m,n)/10);
DD(m,n)=mod(C(m,n),10);
end
end
S = idwt2(cA,cH,VV,DD,'db4',sX);

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Aiswarya Subramanian
Aiswarya Subramanian on 4 Jul 2019
Hello Sultan,
Could you send the error message? In your code you have initialised x = 0.3, which is a scalar. So x(n-1) will give rise to an error.
Also, after your for loop statement, you have put a semi colon (as shown below)
>> for n=2:4;
Hope this helps :)
  2 Comments
KALYAN ACHARJYA
KALYAN ACHARJYA on 4 Jul 2019
Edited: KALYAN ACHARJYA on 4 Jul 2019
Also, after your for loop statement, you have put a semi colon (as shown below)
>> for n=2:4;
No @Aiswarya, it does not matter, whether you put or not.
Let's Keep Learning!

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