Find first three numbers in a matrix that satisfy the condition x>0.001

I have a matrix with three columns and just over 8000 rows. The first column is the load in a compression test as time goes on. I want to find where the numbers start increasing actually increasing, so I want to find the first three numbers which are greater than or equal to 0.001. I've used the following to find the rows where x>0.001:

B=find(A(:,1)>0.001)

However, I don't know how to specifiy to find the first three rows that satisfy these conditions. Any ideas on how to go about this?

Answer 1

[Matt J]

B=find(A(:,1)>0.001,3)

[Zona Hrnjak]

Is there a way to get the first three rows that both satisfy the condition and are next to each other?

[Matt J]

B=A(:,1)>0.001;
C=B(1:end-2)&B(2:end-1)&B(3:end);

result = find(C,1)