Surface of a equation
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I want to plot the quadratic surface of a sphere:
x^2 + y^2 + z^2 = r , where r is equal to 1. Therefore:
x^2 + y^2 + z^2 = 1, where x, y and z are values between -1.5 and 1.5
Can anyone explain me how to do this? I've looked into mesh surfaces but I can only plot functions ( f(x,y) )..
Any help will be highly appreciated. Thanks.
Wayne King on 15 Sep 2012
Edited: Wayne King on 15 Sep 2012
I think you meant to square r in your equation, and you cannot have a value between -1.5 and 1.5 if the radius is 1. The radius has to be 1.5. Think about what happens if x=0,y=0,z=1.5 as you stated must be a point that satisfies the equation x^2+y^2+z^2 = r^2
You should probably do it with spherical coordinates:
n = 100;
r = 1.5;
theta = (-n:2:n)/n*pi;
phi = (-n:2:n)'/n*pi/2;
cosphi = cos(phi); cosphi(1) = 0; cosphi(n+1) = 0;
sintheta = sin(theta); sintheta(1) = 0; sintheta(n+1) = 0;
x = r*cosphi*cos(theta);
y = r*cosphi*sintheta;
z = r*sin(phi)*ones(1,n+1);
xlabel('X'); ylabel('Y'); zlabel('Z')
Note that MATLAB has a function for this with a unit sphere, sphere.m
More Answers (3)
Jürgen on 15 Sep 2012
Javier on 15 Sep 2012
Edited: Walter Roberson on 11 Nov 2020
Procedure done in Matlab R2012.
The problem that you want to solve gives complex solution for Z for arbitrary X and Y in [-1.5,1.5]. The square of X^2 + Y.^2 must be lower than 1, in other case,the solution for Z is a complex number (mesh function doesnt support complex data). To prove it, solve for Z. You get an square root of (1-(X.^2+Y.^2)). I show how to solve for arbitrary number X and Y lower than 0.70 (0.7071^2= 0.5).
Data=randn(10,10) % 10 is arbitrary. Matriz square.
%Define limits of Data Matriz
%Divide Data matriz in two
%For arbitrary X and Y value Z must solve the equality
If this solve your question please grade or make a comment to this answer. Best regards