why the script show wrong output can you help me?

Recall from Physics that, given a position function of a curve in three-dimensional space, the first derivative represents the velocity and the second derivative represents the acceleration at any given time t.

Given the curve r( t ) = < 2*cos( t ), 2*sin( t ), 3*t >, find the position vector pos, velocity vector v, and acceleration vector a at t = 3*pi/2. Then plot the curve using the plot3command over the interval tplot=[0:0.01:2*pi]; and use the code given to view the position, velocity, and acceleration vectors.

% Define variables and functions

syms t;

f=@(t)2*cos(t);

g=@(t)2*sin(t);

h=@(t)3*t;

r=[f(t) g(t) h(t)];

% Find position, velocity, and acceleration vectors

pos=subs(r) % Evaluate at t=3*pi/2

dr=diff(r); % First derivative

v=subs(dr) % Evaluate at t=3*pi/2

d2r=diff(dr); % Second derivative

a=subs(d2r) % Evaluate at t=3*pi/2

%

% Plot curve

tplot=[0:0.01:2*pi];

x=pos;

y=v;

z=a;

p=plot3(x,y,z);

%

% LEAVE ALL REMAINING CODE AS IS

% Plot position from origin and vel/accel from point on curve

hold on

plot3([0 pos(1)],[0 pos(2)],[0 pos(3)],'-k','LineWidth',1); % Plots a line from the origin to the position point

plot3(pos(1),pos(2),pos(3),'*'); % Plots a symbol at the end of the line

plot3([pos(1) pos(1)+v(1)],[pos(2) pos(2)+v(2)],[pos(3) pos(3)+v(3)],'-r','LineWidth',1); % Plots the velocity line starting at the position point

plot3(pos(1)+v(1),pos(2)+v(2),pos(3)+v(3),'*');

plot3([pos(1) pos(1)+a(1)],[pos(2) pos(2)+a(2)],[pos(3) pos(3)+a(3)],'-b','LineWidth',1); % Plots the acceleration line starting at the position point

plot3(pos(1)+a(1),pos(2)+a(2),pos(3)+a(3),'*');

legend('curve', 'position', '', 'velocity', '', 'acceleration','');

OUTPUT

pos =

[ 2*cos(t), 2*sin(t), 3*t]

v =

[ -2*sin(t), 2*cos(t), 3]

a =

[ -2*cos(t), -2*sin(t), 0]

Error using plot3

Data must be numeric, datetime, duration or an array convertible to double.

Error in solution (line 20)

p=plot3(x,y,z);

Answer 1

[Matt J]

tplot=[0:0.01:2*pi];

x=double(subs(pos,tplot));
y=double(subs(v,tplot));
z=double(subs(a,tplot));

p=plot3(x,y,z);

[Stephen23]

Khulood Alhashmi's "Answer" moved here and formatted correctly:

when i put these in the script

tplot=[0:0.01:2*pi];
x=double(subs(pos,tplot));
y=double(subs(v,tplot));
z=double(subs(a,tplot));
p=plot3(x,y,z); 

the output shows an error

pos =
 
[ 2*cos(t), 2*sin(t), 3*t]
 
v =
 
[ -2*sin(t), 2*cos(t), 3]
 
a =
 
[ -2*cos(t), -2*sin(t), 0]
Error using plot3
Data must be numeric, datetime, duration or an array convertible to double.
Error in solution (line 25)
plot3([0 pos(1)],[0 pos(2)],[0 pos(3)],'-k','LineWidth',1);  % Plots a line from the origin to the position point

[Matt J]

It's the same issue. pos(1), pos(2) etc... need to be converted to doubles.

[Khulood Alhashmi]

Can you show me how can I convert it to double please?

[Matt J]

See here.