I have a cell array with arrays of values 0 and I want to clear those

I have an array cell with arrays containing 0 values. I want to remove those zero values but I keep getting an exception for my for loop.Index exceeds matrix dimensions.

My code is:

for i = 1:1:100

Fitness(c{i})

if ans == 0 || ans == 1

c(i) = [];

end

end

Answer 1

[Stephen23]

"I keep getting an exception for my for loop.Index exceeds matrix dimensions."

You get this error precisely because you are removing elements from the cell array. Think about what happens when you remove one element: then the array is smaller but you are still iterating over its original length, not the shortened length, so you end up trying to index into elements that no longer exist.

Here are two easy solutions:

Method one: iterate backwards:

for k = 100:-1:1 % backwards!
    out = Fitness(c{k});
    if out==0 || out==1;
        c(k) = [];
    end
end

Method two: remove after the loop:

idx = false(1,100);
for k = 1:1:100
     out = Fitness(c{k});
     idx(k) =  out==0 || out==1;
end
c(idx) = []

This is will generally be more efficient.

[N/A]

Thank you I understood method 1 but can you explain method 2?