where is my fault?

Age=input("Age of the person is:","s");

find (Age<16);
disp(["Sorry-You will have to wait. You are only  " Age])

find (Age>=16)&(Age<18);
disp(["You may have a youth license because you are   " Age])

find (Age>=18)&(Age<=70);
disp(["You may have license because you are   " Age])

Answer 1

[Steven Lord]

The find function just tells you which elements of its input are true. It doesn't actually select if the next line of code should run or should be skipped.

There's no need for the find function here except the homework problem requires it. But find alone will not do the job. See the help for if as well.

Finally, in your input statement you don't want to use "s".

>> age1 = input("Enter your age: ", "s")
Enter your age: 19
age1 =
    '19'

>> age2 = input("Enter your age: ")
Enter your age: 19
age2 =
    19

>> whos age1 age2
  Name      Size            Bytes  Class     Attributes

  age1      1x2                 4  char                
  age2      1x1                 8  double              

You don't want the age as text (age1) you want it as a number (age2).

[Irem Deniz]

sorry but this is not the answer to my question. I never understood what you did.

When I enter age data without using if, I want it to answer only one, according to the above constraints.

[Steven Lord]

None of the functions you use in the code you've posted has any decision making capability. There's no control flow. To make a decision you're going to need to use if or something like it. find can be used as part of the solution but it is not the whole solution.

[John D'Errico]

While it really is the answer to your question, I think the real problem is you need to read the getting started tutorials in MATLAB. Try the MATLAB Onramp course, as you don't seem to appeciate what find does, or what an if statement does. These are basic concepts you will see in a getting started tutorial.

[Irem Deniz]

Do you see the screenshot I mentioned in the attachment? He wants him to return to me according to the inputs I have entered in the question. I could not find how to do this. I'm writing here because I can't find it. I thought I should do it without using "if" because it says use "find" in the question. When I do it by typing if-elseif-else, I never get a result. Maybe I can understand if you can answer according to my question.

Thank you

[Irem Deniz]

like this,

Age=input("Age of the person is:","s");
if find (Age<16);
    disp(["Sorry-You will have to wait. You are only  " Age])
elseif find (Age>=16)&(Age<18);
    disp(["You may have a youth license because you are   " Age])
else find (Age>=18)&(Age<=70);
    disp(["You may have license because you are   " Age])
end

[Steven Lord]

You're almost there. The only problem is the "s" in your input call.

find('17' < 18)

ans =

  1×0 empty double row vector

Why? Because the ASCII value of the character '1' is greater than 18, as is the ASCII value of the character '7'.

double('1')

ans = 49

double('7')

ans = 55

You can accept the value the user inputs as text (by passing the "s" option to input) then convert it to a number for use in the find statements and use the text form in your disp statements. Alternately you can accept the value the user inputs as a number (no "s" option), use that number in the find statement, and convert it to text for use in disp. Since you're working with a string array the latter is IMO easier.

age = 17;
disp(["Happy birthday! You are " + age + " years old today!"])

Happy birthday! You are 17 years old today!

[Irem Deniz]

How can I make it give results by comparing between inputs I have entered?