optical power vs distance

7 views (last 30 days)
abdullah qasim
abdullah qasim on 26 Jan 2021
Answered: Rohit Pappu on 29 Jan 2021
How can I draw a chart of the average power versus the distance, as in the following figure for knowledge that the value of the average power (1 * 101), i.e. a matrix, and the distance between the light source and the light receiver is 3 meters
Assuming average power = Paver
Distance = h

Accepted Answer

Rohit Pappu
Rohit Pappu on 29 Jan 2021
A plausible solution
clf;
figure;
% Create a distance vector of range 1m to 3m
distance = linspace(1,3,101);
hold on
% plot a line with color red
plot(distance,Paver,'r');
% To plot the markers
% plot(x variable, y variable,'Marker','+');
hold off
% Set the title, x-axis and y-axis
title('Average Power as a function of distance');
xlabel('Distance in meters');
ylabel('Optical Power');

More Answers (0)

Categories

Find more on Wireless Communications in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!