Inversion of a 5D look-up table

Dear Mathwork coomunity,

I have four 5D Look-Up tables with input and output parameters obtained with the following code using the attached simulation results file.

clc;

clear;

close all;

%read simulation data

Results = readmatrix('Stator_separeted.xlsx');

AngleR=Results(:,1);

AngleL=Results(:,2);

MMFL=Results(:,3);

MMFR=Results(:,4);

move=Results(:,5);

Torque=Results(:,6)*0.001;

Force=Results(:,7);

FluxL=Results(:,8);

FluxR=Results(:,9);

turns = 100; % number of turns;

% converting of simulation data

CurrentR = MMFR./turns;

CurrentL = MMFL./turns;

FluxLinkageL = FluxL*turns;

FluxLinkageR = FluxR*turns;

%axis vectors of 5D-Look-Up table (input simulation parameters)

AngleRvec = [-40;-35;-30;-25;-20;-15;-10;-5;0];

AngleLvec = [-40;-35;-30;-25;-20;-15;-10;-5;0];

CurrentLvec = [-700/turns; 0/turns; 700/turns; 1400/turns; 2100/turns];

CurrentRvec = [-700/turns; 0/turns; 700/turns; 1400/turns; 2100/turns];

movevec = [-4; -2; 0; 2; 4];

%reshape vectors of output simulation parameters to 5D-arrays

reshapeVec = [9 9 5 5 5];

FluxLinkageL = reshape(FluxLinkageL,reshapeVec);

FluxLinkageR = reshape(FluxLinkageR,reshapeVec);

Torque = reshape(Torque,reshapeVec);

Force = reshape(Force,reshapeVec);

My question is - how can these four 5D LUTs be inversed to the eight following 4D LUTs:

Inversion of Force-LUT Force(AngleR, AngleL, CurrentL, CurrentR, move) to CurrentL(AngleR, AngleL, Force,move) and CurrentR(AngleR, AngleL, Force,move);

Inversion of Torque-LUT: Torque(AngleR, AngleL, CurrentL, CurrentR, move) to CurrentL(AngleR, AngleL, Torque,move) and CurrentR(AngleR, AngleL, Torque,move);

Inversion of FluxLinkageL-LUT: FluxLinkageL(AngleR, AngleL, CurrentL, CurrentR, move) to CurrentL(AngleR, AngleL, FluxLinkageL,move) and CurrentR(AngleR, AngleL, FluxLinkageL,move);

Inversion of FluxLinkageR-LUT: FluxLinkageL(AngleR, AngleL, CurrentL, CurrentR, move) to CurrentL(AngleR, AngleL, FluxLinkageR,move) and CurrentR(AngleR, AngleL, FluxLinkageR,move).

Of course, if one of these LUTs can be inversed, the remaining can be inversed in the same way.

Please help me with this question.