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How to run the function again after a error?

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Ibrahim A
Ibrahim A on 16 May 2021
Answered: Aditya Patil on 19 May 2021
I am having a function where I input a time limit (T_limit) and in the body of the program some independent time(T_7) calculated. I am writing comparing these 2 time varibales, if the T_limit>T_7, function executes normally, but if the T_7 > T_limit, error message thrown and ask user to input a new time(T_limit) and executes the function again with this value. My problem is that, my code stuct in a infinite loop. Is there a way to execute function again with this new variable(T_limit)?
function [motion] = motionPlanning(j_max,a_max,v_max,length,T_limit)
%...
%%% FC2 - Time Violation
if (T7<T_limit) || (T_limit == 0)
disp("### MP - FC2 + Time is not violated (DSP) ###" );
motion.mp_feasibility{1,1} = ["Time Violation ", true];
else
motion.mp_feasibility{1,1} = ["Time Violation ", false];
try
error("### MP - FC2 + Time has been violated (DSP) ###");
catch
disp("### MP - FC2 + Enter new time limit (DSP) ###");
fprintf("New time limit: %d", T_limit);
[motion] = motionPlanning(2,0,0,200,T_limit);
end
end
  2 Comments
Ibrahim A
Ibrahim A on 16 May 2021
This is the main function not in another function. So if i make another function and call motionPlanning inside this function. Would that eliminate recursion?

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Accepted Answer

Aditya Patil
Aditya Patil on 19 May 2021
I would recommend separating the logic of the function and the code to take inputs from the user. Two of the possible ways to do this are,
  1. The function can verify the input and throw error if they are invalid. An outer while loop asks for input from the user, calls the functions, and repeats if the function throws an error. Else, the while loop exists.
  2. The outer loop verifies the inputs and calls the function only if the inputs are valid. Else, it asks for the inputs from user again.

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