Why do I get a wrong answer when I use FIND function in this case?

3 views (last 30 days)
I have a graph structure "G_dmg.Nodes.Load" which has typically 40 "-inf" values and 10 other numbers ~= -inf.
In my script:
inActive = find(G_dmg.Nodes.Load==-inf);
for ii = 1:length(inActive)
b = neighbors(G_dmg,inActive(ii));
idx = find(G_dmg.Nodes.Load(b)~= -inf);
Load = G_dmg.Nodes.Load(idx);
end
So, I'm trying to find the indices of inActive nodes' neighbors that do not have -inf Load values. FIND function is not giving me back the correct indices.
say b = [10 11 2 3 4] and the 10th, 11th entries in G_dmg.Nodes.Load ~=-inf but 2nd, 3rd, 4th have -inf values. idx variable in my script is giving me back 1 2 which are basically are the first and second entries in b.

Accepted Answer

Rik
Rik on 17 Jun 2021
When you subindex a variable before using find, it will return the indices relative to that subindexed variable. This is because find doesn't know about the indexing.
This might fix the problem:
idx=b(idx);

More Answers (1)

KSSV
KSSV on 17 Jun 2021
Edited: KSSV on 17 Jun 2021
Replace the line:
inActive = find(G_dmg.Nodes.Load==-inf);
with
idx = isinf(G_dmg.Nodes.Load) ;
inActive = find(sign(G_dmg.Nodes.Load).*idx == -1)
Follow the same for other lines where you are trying to find -inf.
You can achieve the above without loop.
  1 Comment
Waseem AL Aqqad
Waseem AL Aqqad on 17 Jun 2021
Thanks for telling me this technique.
Unfortunately, I have to use a loop here since the built in function "neighbors" accepts only scalar inputs, I can't pass the vector inActive to it.
I believe it has this ristriction as each node in a graph has different number of neighboring nodes. Of course, I can concatenate them like this:
b = [];
b = [b, neighbors(G_dmg,inActive(ii))];
But still, I cannot tell which nodes are neighbors to node X and which are neighbors to node Y.

Sign in to comment.

Categories

Find more on Graph and Network Algorithms in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!