Solution 311131

Submitted on 27 Aug 2013

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2 Comments

2 Comments

niko_k on 27 Aug 2013

solution is correct in my opinion.

Tim on 27 Aug 2013

rand(1,1)*5+1 will produce random numbers uniformly distributed between 1 and 6; round will convert values from 1 to 1.5 to 1, and values from 1.5 to 2.5 to 2, so 1 will occur only about half as often as 2. Overall, 1 and 6 will occur only about half as often as 2, 3, 4, and 5.

Test Suite

Test	Status	Code Input and Output
1	Fail	%% x1 = zeros(1,6000); x2 = zeros(1,6000); for ii = 1:6000 [x1(ii),x2(ii)] = rollDice(); end numCt = sum( bsxfun( @eq, x1, (1:6)' ), 2 ) + sum( bsxfun( @eq, x2, (1:6)' ), 2 ); assert(all(round(numCt/200) == 10) && sum(numCt) == 12000) Error: Assertion failed.

Test

Status

Code Input and Output

Fail

%% x1 = zeros(1,6000); x2 = zeros(1,6000); for ii = 1:6000 [x1(ii),x2(ii)] = rollDice(); end numCt = sum( bsxfun( @eq, x1, (1:6)' ), 2 ) + sum( bsxfun( @eq, x2, (1:6)' ), 2 ); assert(all(round(numCt/200) == 10) && sum(numCt) == 12000)

Error: Assertion failed.

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