Cody

Solution 1564304

Submitted on 19 Jun 2018 by David Verrelli
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Test Suite

Test Status Code Input and Output
1   Pass
A=[5 8 2 4;1 11 1 5] ; B_correct = [2 8 5 4;1 5 1 11]; assert(isequal(SrtPrimesInRows(A),B_correct))

b = 5 8 2 4 pIdx = 1×4 logical array 1 0 1 0 p = 5 2 b = 2 8 5 4 B = 2 8 5 4 1 11 1 5 b = 1 11 1 5 pIdx = 1×4 logical array 0 1 0 1 p = 11 5 b = 1 5 1 11 B = 2 8 5 4 1 5 1 11

2   Pass
A=[2 7 5; 1 11 2;2 2 2]; B_correct=[2 5 7;1 2 11;2 2 2]; assert(isequal(SrtPrimesInRows(A),B_correct))

b = 2 7 5 pIdx = 1×3 logical array 1 1 1 p = 2 7 5 b = 2 5 7 B = 2 5 7 1 11 2 2 2 2 b = 1 11 2 pIdx = 1×3 logical array 0 1 1 p = 11 2 b = 1 2 11 B = 2 5 7 1 2 11 2 2 2 b = 2 2 2 pIdx = 1×3 logical array 1 1 1 p = 2 2 2 b = 2 2 2 B = 2 5 7 1 2 11 2 2 2

3   Pass
A=[111 12 134;333 654 100000;112227 38 1]; B_correct=A; assert(isequal(SrtPrimesInRows(A),B_correct))

b = 111 12 134 pIdx = 1×3 logical array 0 0 0 p = 1×0 empty double row vector b = 111 12 134 B = 111 12 134 333 654 100000 112227 38 1 b = 333 654 100000 pIdx = 1×3 logical array 0 0 0 p = 1×0 empty double row vector b = 333 654 100000 B = 111 12 134 333 654 100000 112227 38 1 b = 112227 38 1 pIdx = 1×3 logical array 0 0 0 p = 1×0 empty double row vector b = 112227 38 1 B = 111 12 134 333 654 100000 112227 38 1

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