Cody

Problem 44309. Pi Digit Probability

Solution 2543745

Submitted on 13 Jun 2020 by Nabil Chowdhury
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Test Suite

Test Status Code Input and Output
1   Pass
N = 101; n = 3; y_correct = 0.1200; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match')))) % modified from the comment of Alfonso on https://www.mathworks.com/matlabcentral/cody/problems/44343

y = 0.1200
2   Pass
N = 201; n = 6; y_correct = 0.0750; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match'))))

y = 0.0750
3   Pass
N = 202; n = 6; y_correct = 0.0796; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match'))))

y = 0.0796
4   Pass
N = 203; n = 6; y_correct = 0.0792; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match'))))

y = 0.0792
5   Pass
N = 1001; n = 9; y_correct = 0.1050; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match'))))

y = 0.1050

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