Cody

# Problem 44455. Find the average of a random sequance

Solution 1910163

Submitted on 23 Aug 2019
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### Test Suite

Test Status Code Input and Output
1   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'regexp')),'regexp hacks are forbidden')

2   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'sum')),'sum() function is forbidden')

3   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'mean')),'mean() function is forbidden')

4   Pass
rng(1); av_correct = 5.5; assert(isequal(MeanWhile(),av_correct))

ans = 3 average = 5.5000

5   Pass
rng(2); av_correct = 4; assert(isequal(MeanWhile(),av_correct))

ans = 2 average = 4

6   Pass
rng(3); av_correct = 5.25; assert(isequal(MeanWhile(),av_correct))

ans = 9 average = 5.2500

7   Fail
rng(7); av_correct = 0; assert(isequal(MeanWhile(),av_correct))

ans = 1 average = NaN

Assertion failed.

8   Pass
rng(0); av_correct = 6.571428571428571; assert(isequal(MeanWhile(),av_correct))

ans = 22 average = 6.5714