{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2025-12-14T01:33:56.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2025-12-14T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":767,"title":"Assign numerical values to a structure with 1 field","description":"The aim is to assign values to a multidimensional structure  *without using for-loop or while-loop*\r\n\r\nExample with a structure 2*3:\r\n\r\n  s = repmat(struct('prices', 0), 2, 3);\r\n  data = [11 12 13 ;21 22 23 ];\r\n\r\nThe expected output s2 will be the following structure 2*3:\r\n\r\n   s2(1,1).prices = 11\r\n   s2(1,2).prices = 12\r\n   s2(1,3).prices = 13\r\n   s2(2,1).prices = 21 \r\n   s2(2,2).prices = 22\r\n   s2(2,3).prices = 23\r\n\r\nRules:\r\n\r\n1) Using For-loops or While-loops is prohibited \r\n\r\n2) For this problem the structure will always have *a single field*. In the above example s has an unique field \"prices\". \r\n\r\n3) However the *name of this field can be changed*\r\n\r\nHave fun!","description_html":"\u003cp\u003eThe aim is to assign values to a multidimensional structure  \u003cb\u003ewithout using for-loop or while-loop\u003c/b\u003e\u003c/p\u003e\u003cp\u003eExample with a structure 2*3:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003es = repmat(struct('prices', 0), 2, 3);\r\ndata = [11 12 13 ;21 22 23 ];\r\n\u003c/pre\u003e\u003cp\u003eThe expected output s2 will be the following structure 2*3:\u003c/p\u003e\u003cpre\u003e   s2(1,1).prices = 11\r\n   s2(1,2).prices = 12\r\n   s2(1,3).prices = 13\r\n   s2(2,1).prices = 21 \r\n   s2(2,2).prices = 22\r\n   s2(2,3).prices = 23\u003c/pre\u003e\u003cp\u003eRules:\u003c/p\u003e\u003cp\u003e1) Using For-loops or While-loops is prohibited\u003c/p\u003e\u003cp\u003e2) For this problem the structure will always have \u003cb\u003ea single field\u003c/b\u003e. In the above example s has an unique field \"prices\".\u003c/p\u003e\u003cp\u003e3) However the \u003cb\u003ename of this field can be changed\u003c/b\u003e\u003c/p\u003e\u003cp\u003eHave fun!\u003c/p\u003e","function_template":"function s2= assign_struct(s,data)\r\n s2 = data;\r\nend","test_suite":"%%\r\ns = repmat(struct('prices', 0), 2, 3);\r\ndata = [11 12 13 ;21 22 23 ];\r\n\r\n% solution\r\n s2(1,1).prices = 11\r\n s2(1,2).prices = 12\r\n s2(1,3).prices = 13\r\n s2(2,1).prices = 21 \r\n s2(2,2).prices = 22\r\n s2(2,3).prices = 23\r\nassert(isequal(assign_struct(s,data),s2))\r\n\r\n% prevents cheating\r\nfiletext = fileread('assign_struct.m')\r\n assert(isempty(strfind(filetext, 'for')))\r\n assert(isempty(strfind(filetext, 'while')))\r\n\r\n%% Another fieldname\r\ns = repmat(struct('yo', 0), 2, 3);\r\ndata = [14 12 13 ;87 22 2.3 ];\r\n\r\n% solution\r\n s2(1,1).yo = 14\r\n s2(1,2).yo = 12\r\n s2(1,3).yo = 13\r\n s2(2,1).yo = 87 \r\n s2(2,2).yo = 22\r\n s2(2,3).yo = 2.3\r\nassert(isequal(assign_struct(s,data),s2))\r\n\r\n% prevents cheating\r\nfiletext = fileread('assign_struct.m')\r\n assert(isempty(strfind(filetext, 'for')))\r\n assert(isempty(strfind(filetext, 'while')))\r\n\r\n%% structure bigger with a random matrix\r\ns = repmat(struct('french', 0), 4, 4);\r\ndata = rand(4);\r\n\r\nfor i = 1:4\r\n      for j = 1:4\r\n          s2(i,j).french = data(i,j);\r\n      end\r\nend\r\nassert(isequal(assign_struct(s,data),s2))\r\n\r\n\r\n% prevents cheating\r\nfiletext = fileread('assign_struct.m')\r\n assert(isempty(strfind(filetext, 'for')))\r\n assert(isempty(strfind(filetext, 'while')))","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":639,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":34,"test_suite_updated_at":"2012-06-15T12:32:22.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2012-06-15T09:08:05.000Z","updated_at":"2025-12-09T17:36:19.000Z","published_at":"2012-06-15T09:08:05.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe aim is to assign values to a multidimensional structure \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ewithout using for-loop or while-loop\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample with a structure 2*3:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[s = repmat(struct('prices', 0), 2, 3);\\ndata = [11 12 13 ;21 22 23 ];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe expected output s2 will be the following structure 2*3:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[   s2(1,1).prices = 11\\n   s2(1,2).prices = 12\\n   s2(1,3).prices = 13\\n   s2(2,1).prices = 21 \\n   s2(2,2).prices = 22\\n   s2(2,3).prices = 23]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eRules:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e1) Using For-loops or While-loops is prohibited\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e2) For this problem the structure will always have\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ea single field\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e. In the above example s has an unique field \\\"prices\\\".\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e3) However the\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ename of this field can be changed\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHave fun!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":43685,"title":"Apply Function to Each Field of a Structure Array: Part 1","description":"The builtin \u003chttp://www.mathworks.com/help/matlab/ref/structfun.html?=structfun structfun\u003e applies a function handle to each field of a *scalar structure*, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\r\n\r\nWrite your own function *structfun2* which accepts a structure array *s* and a function handle *f* as the inputs. The output *c = structfun2(f,s)* is a cell array of the same size as *s*, with each cell storing the result of *f* applied to every field of the relevant structure element in *s*. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, structfun2(f,s) = structfun(f,s) holds for any scalar structure *s*. The assumption required is that *f* is a function that returns a scalar, regardless of the input. \r\n\r\nExample: \r\n\r\n  s = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\n  f = @numel;\r\n  c = {[1;2], [2;1]; [1;3], [2;2]};\r\n\r\nRelated problems in this series:\r\n\r\n* \u003chttp://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2 Apply Function to Each Field of a Structure Array: Part 2\u003e\r\n* \u003chttp://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1 Apply Function to Each Field of a Structure Array: Part 1\u003e","description_html":"\u003cp\u003eThe builtin \u003ca href = \"http://www.mathworks.com/help/matlab/ref/structfun.html?=structfun\"\u003estructfun\u003c/a\u003e applies a function handle to each field of a \u003cb\u003escalar structure\u003c/b\u003e, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\u003c/p\u003e\u003cp\u003eWrite your own function \u003cb\u003estructfun2\u003c/b\u003e which accepts a structure array \u003cb\u003es\u003c/b\u003e and a function handle \u003cb\u003ef\u003c/b\u003e as the inputs. The output \u003cb\u003ec = structfun2(f,s)\u003c/b\u003e is a cell array of the same size as \u003cb\u003es\u003c/b\u003e, with each cell storing the result of \u003cb\u003ef\u003c/b\u003e applied to every field of the relevant structure element in \u003cb\u003es\u003c/b\u003e. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, structfun2(f,s) = structfun(f,s) holds for any scalar structure \u003cb\u003es\u003c/b\u003e. The assumption required is that \u003cb\u003ef\u003c/b\u003e is a function that returns a scalar, regardless of the input.\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003es = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\nf = @numel;\r\nc = {[1;2], [2;1]; [1;3], [2;2]};\r\n\u003c/pre\u003e\u003cp\u003eRelated problems in this series:\u003c/p\u003e\u003cul\u003e\u003cli\u003e\u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2\"\u003eApply Function to Each Field of a Structure Array: Part 2\u003c/a\u003e\u003c/li\u003e\u003cli\u003e\u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1\"\u003eApply Function to Each Field of a Structure Array: Part 1\u003c/a\u003e\u003c/li\u003e\u003c/ul\u003e","function_template":"function y = structfun2(f,s)\r\n  y = x;\r\nend","test_suite":"%%\r\ns.f1 = 'Sunday';\r\ns.f2 = 'Monday';\r\ns.f3 = 'Tuesday'; \r\ns.f4 = 'Wednesday';\r\ns.f5 = 'Thursday';\r\ns.f6 = 'Friday';\r\ns.f7 = 'Saturday';\r\nf = @numel;\r\nc = structfun(@numel, s);\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\nf = @(x)min(x(:));\r\nc = {[1;1], [3;2]; [1;3], [5;2]};\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\nf = @(x)max(x(:));\r\nc = {[1;2], [4;2]; [1;5], [6;5]};\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{0, [3 4]; 1, [5 7 6]},'f2',{[0 0], 2; [2 4 5], [0 5]});\r\nf = @nnz;\r\nc = {[0;0], [2;1]; [1;3], [3;1]};\r\nassert(isequal(structfun2(f,s),c))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":12569,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":31,"test_suite_updated_at":"2016-12-01T22:39:09.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2016-11-27T01:04:06.000Z","updated_at":"2025-12-14T11:39:11.000Z","published_at":"2016-11-27T01:32:39.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe builtin\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/help/matlab/ref/structfun.html?=structfun\\\"\u003e\u003cw:r\u003e\u003cw:t\u003estructfun\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e applies a function handle to each field of a\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003escalar structure\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eWrite your own function\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003estructfun2\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e which accepts a structure array\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e and a function handle\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e as the inputs. The output\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ec = structfun2(f,s)\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is a cell array of the same size as\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e, with each cell storing the result of\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e applied to every field of the relevant structure element in\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, structfun2(f,s) = structfun(f,s) holds for any scalar structure\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e. The assumption required is that\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is a function that returns a scalar, regardless of the input.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[s = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\\nf = @numel;\\nc = {[1;2], [2;1]; [1;3], [2;2]};]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eRelated problems in this series:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eApply Function to Each Field of a Structure Array: Part 2\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eApply Function to Each Field of a Structure Array: Part 1\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":689,"title":"Sort an array of structures","description":"You need to sort an array of structures based upon *a numeric first field*:\r\n\r\nFor example :\r\n\r\n  a.n=1;\r\n  a.name='a';\r\n  b.n=3;\r\n  b.name='b';\r\n  c.n=2;\r\n  c.name='c';\r\n  array = [a b c]\r\n\r\nThis array of 3 structures is not sorted yet since:\r\n\r\n  \u003e\u003e array(2)\r\n\r\nshows:\r\nans = \r\n\r\n       n: 3\r\n    name: 'b'\r\n\r\nThe aim is to have for this example the output _array_ such as :\r\n\r\n  \u003e\u003e array(1)\r\n  \r\n  ans = \r\n  \r\n         n: 1\r\n      name: 'a'\r\n  \r\n  \u003e\u003e array(2)\r\n  \r\n  ans = \r\n  \r\n         n: 2\r\n      name: 'c'\r\n  \r\n  \u003e\u003e array(3)\r\n  \r\n  ans = \r\n  \r\n         n: 3\r\n      name: 'b'\r\n  \r\n\r\nThe input of this problem is an array of structures. .","description_html":"\u003cp\u003eYou need to sort an array of structures based upon \u003cb\u003ea numeric first field\u003c/b\u003e:\u003c/p\u003e\u003cp\u003eFor example :\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003ea.n=1;\r\na.name='a';\r\nb.n=3;\r\nb.name='b';\r\nc.n=2;\r\nc.name='c';\r\narray = [a b c]\r\n\u003c/pre\u003e\u003cp\u003eThis array of 3 structures is not sorted yet since:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003e\u003e\u003e array(2)\r\n\u003c/pre\u003e\u003cp\u003eshows:\r\nans =\u003c/p\u003e\u003cpre\u003e       n: 3\r\n    name: 'b'\u003c/pre\u003e\u003cp\u003eThe aim is to have for this example the output \u003ci\u003earray\u003c/i\u003e such as :\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003e\u003e\u003e array(1)\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003eans = \r\n\u003c/pre\u003e\u003cpre\u003e         n: 1\r\n      name: 'a'\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e\u003e\u003e array(2)\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003eans = \r\n\u003c/pre\u003e\u003cpre\u003e         n: 2\r\n      name: 'c'\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e\u003e\u003e array(3)\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003eans = \r\n\u003c/pre\u003e\u003cpre\u003e         n: 3\r\n      name: 'b'\u003c/pre\u003e\u003cp\u003eThe input of this problem is an array of structures. .\u003c/p\u003e","function_template":"function array_sorted = your_fcn_name(array)\r\n  array_correct  = array;\r\nend","test_suite":"%% Test the example\r\na.n=1;\r\na.name='a';\r\nb.n=3;\r\nb.name='b';\r\nc.n=2;\r\nc.name='c';\r\narray = [a b c]\r\n\r\n% solution based on the first numeric field :\r\narray_sorted = [a c b]\r\n\r\nassert(isequal(your_fcn_name(array),array_sorted))\r\n\r\n%% Another test\r\ns1.age = 33\r\ns1.name = 'aurelien'\r\ns2.age = 25\r\ns2.name = 'jeanpierre'\r\narray = [s1 s2 ]\r\n\r\n% solution based on the first numeric field :\r\narray_sorted = [s2 s1]\r\n\r\nassert(isequal(your_fcn_name(array),array_sorted))","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":639,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":49,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2012-05-14T08:20:20.000Z","updated_at":"2025-12-07T19:33:55.000Z","published_at":"2012-05-14T08:20:20.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou need to sort an array of structures based upon\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ea numeric first field\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example :\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[a.n=1;\\na.name='a';\\nb.n=3;\\nb.name='b';\\nc.n=2;\\nc.name='c';\\narray = [a b c]]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThis array of 3 structures is not sorted yet since:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[\u003e\u003e array(2)]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eshows: ans =\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[       n: 3\\n    name: 'b']]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe aim is to have for this example the output\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003earray\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e such as :\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[\u003e\u003e array(1)\\n\\nans = \\n\\n         n: 1\\n      name: 'a'\\n\\n\u003e\u003e array(2)\\n\\nans = \\n\\n         n: 2\\n      name: 'c'\\n\\n\u003e\u003e array(3)\\n\\nans = \\n\\n         n: 3\\n      name: 'b']]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe input of this problem is an array of structures. .\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":43686,"title":"Apply Function to Each Field of a Structure Array: Part 2","description":"The builtin \u003chttp://www.mathworks.com/help/matlab/ref/structfun.html?=structfun structfun\u003e applies a function handle to each field of a *scalar structure*, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\r\n\r\nWrite your own function *structfun2* which accepts a structure array *s* and a function handle *f* as the inputs. The output *c = structfun2(f,s)* is a structure array *c* of the same size and same fields as *s*, where each field of the structure element of c stores the result of *f* applied to the same field of the relevant structure element in *s*. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, when *s* is a scalar structure, your output reduces to c = structfun(f,s,'UniformOutput',false). No assumption on *f* is needed in this problem. \r\n \r\n\r\nExample: \r\n\r\n  s = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\n  f = @numel;\r\n  c = struct('f1',{1, 2; 1, 2},'f2',{2, 1; 3, 2});\r\n\r\nRelated problems in this series:\r\n\r\n* \u003chttp://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1 Apply Function to Each Field of a Structure Array: Part 1\u003e\r\n* \u003chttp://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2 Apply Function to Each Field of a Structure Array: Part 2\u003e\r\n","description_html":"\u003cp\u003eThe builtin \u003ca href = \"http://www.mathworks.com/help/matlab/ref/structfun.html?=structfun\"\u003estructfun\u003c/a\u003e applies a function handle to each field of a \u003cb\u003escalar structure\u003c/b\u003e, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\u003c/p\u003e\u003cp\u003eWrite your own function \u003cb\u003estructfun2\u003c/b\u003e which accepts a structure array \u003cb\u003es\u003c/b\u003e and a function handle \u003cb\u003ef\u003c/b\u003e as the inputs. The output \u003cb\u003ec = structfun2(f,s)\u003c/b\u003e is a structure array \u003cb\u003ec\u003c/b\u003e of the same size and same fields as \u003cb\u003es\u003c/b\u003e, where each field of the structure element of c stores the result of \u003cb\u003ef\u003c/b\u003e applied to the same field of the relevant structure element in \u003cb\u003es\u003c/b\u003e. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, when \u003cb\u003es\u003c/b\u003e is a scalar structure, your output reduces to c = structfun(f,s,'UniformOutput',false). No assumption on \u003cb\u003ef\u003c/b\u003e is needed in this problem.\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003es = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\nf = @numel;\r\nc = struct('f1',{1, 2; 1, 2},'f2',{2, 1; 3, 2});\r\n\u003c/pre\u003e\u003cp\u003eRelated problems in this series:\u003c/p\u003e\u003cul\u003e\u003cli\u003e\u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1\"\u003eApply Function to Each Field of a Structure Array: Part 1\u003c/a\u003e\u003c/li\u003e\u003cli\u003e\u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2\"\u003eApply Function to Each Field of a Structure Array: Part 2\u003c/a\u003e\u003c/li\u003e\u003c/ul\u003e","function_template":"function y = structfun2(f,s)\r\n  y = s;\r\nend","test_suite":"%%\r\ns.f1 = 'Sunday';\r\ns.f2 = 'Monday';\r\ns.f3 = 'Tuesday'; \r\ns.f4 = 'Wednesday';\r\ns.f5 = 'Thursday';\r\ns.f6 = 'Friday';\r\ns.f7 = 'Saturday';\r\nf = @(x)x(1:3);\r\nc = structfun(f,s,'UniformOutput',false);\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4;5 6]; 1, [5 6;7 8]},'f2',{[1 2], 2; [3 4 5;6 7 8], [2 6;4 5]});\r\nf = @min;\r\nc = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{1, 2; [3 4 5], [2 5]});\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4;5 6]; 1, [5 6;7 8]},'f2',{[1 2], 2; [3 4 5;6 7 8], [2 6;4 5]});\r\nf = @sum;\r\nc = struct('f1',{1, [8 10]; 1, [12 14]},'f2',{3, 2; [9 11 13], [6 11]});\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4;5 6]; 1, [5 6;7 8]},'f2',{[1 2], 2; [3 4 5;6 7 8], [2 6;4 5]});\r\nf = @pow2;\r\nc = struct('f1',{2, [8 16;32 64]; 2, [32 64;128 256]},'f2',{[2 4], 4; [8 16 32;64 128 256], [4 64;16 32]});\r\nassert(isequal(structfun2(f,s),c))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":1,"created_by":12569,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":24,"test_suite_updated_at":"2016-12-01T22:27:07.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2016-11-27T02:12:26.000Z","updated_at":"2025-12-15T21:01:07.000Z","published_at":"2016-11-27T02:12:31.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe builtin\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/help/matlab/ref/structfun.html?=structfun\\\"\u003e\u003cw:r\u003e\u003cw:t\u003estructfun\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e applies a function handle to each field of a\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003escalar structure\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eWrite your own function\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003estructfun2\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e which accepts a structure array\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e and a function handle\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e as the inputs. The output\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ec = structfun2(f,s)\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is a structure array\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ec\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e of the same size and same fields as\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e, where each field of the structure element of c stores the result of\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e applied to the same field of the relevant structure element in\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, when\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is a scalar structure, your output reduces to c = structfun(f,s,'UniformOutput',false). No assumption on\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is needed in this problem.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[s = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\\nf = @numel;\\nc = struct('f1',{1, 2; 1, 2},'f2',{2, 1; 3, 2});]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eRelated problems in this series:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eApply Function to Each Field of a Structure Array: Part 1\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eApply Function to Each Field of a Structure Array: Part 2\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":688,"title":"Convert a structure into a string","description":"Convert the contents of each fields into a string.\r\n\r\nExample with an input structure s with 2 fields : \r\n\r\n  s.age = '33'\r\n  s.prenom ='aurélien'\r\n  \r\nThe output will be the string of size 1*11 :\r\n\r\n  str =\r\n  \r\n  33\r\n  aurélien\r\n\r\nwhich is the same of typing str = ['33',10,'aurélien']","description_html":"\u003cp\u003eConvert the contents of each fields into a string.\u003c/p\u003e\u003cp\u003eExample with an input structure s with 2 fields :\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003es.age = '33'\r\ns.prenom ='aurélien'\r\n\u003c/pre\u003e\u003cp\u003eThe output will be the string of size 1*11 :\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003estr =\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e33\r\naurélien\r\n\u003c/pre\u003e\u003cp\u003ewhich is the same of typing str = ['33',10,'aurélien']\u003c/p\u003e","function_template":"function str = your_fcn_name(s)\r\n  y = x;\r\nend","test_suite":"%%\r\ns.age = '33'\r\ns.prenom ='aurélien'\r\nstr_correct = ['33',10,'aurélien'];\r\nassert(isequal(your_fcn_name(s),str_correct))\r\n\r\n%%\r\ns.f1 = 'Sunday'; \r\ns.f2 = 'Monday'; \r\ns.f3 = 'Tuesday';\r\ns.f4 = 'Wednesday'; \r\ns.f5 = 'Thursday'; \r\ns.f6 = 'Friday';\r\ns.f7 = 'Saturday';\r\nstr_correct = ['Sunday',10,'Monday',10,'Tuesday',10,'Wednesday',10,'Thursday',10,'Friday',10,'Saturday'];\r\nassert(isequal(your_fcn_name(s),str_correct))\r\n\r\n%%\r\ns.age = '42';\r\ns.height = '73.5';\r\ns.weight = '173';\r\nstr_correct = ['42',10,'73.5',10,'173'];\r\nassert(isequal(your_fcn_name(s),str_correct))\r\n\r\n%%\r\ns.hair = 'brown';\r\ns.eye = 'green';\r\ns.fav = 'gold';\r\nstr_correct = ['brown',10,'green',10,'gold'];\r\nassert(isequal(your_fcn_name(s),str_correct))\r\n\r\n%%\r\ns.first = 'Tom';\r\ns.second = 'Jeff';\r\ns.third = 'Bill';\r\ns.fourth = 'Jerry';\r\ns.fifth = 'Harold';\r\nstr_correct = ['Tom',10,'Jeff',10,'Bill',10,'Jerry',10,'Harold'];\r\nassert(isequal(your_fcn_name(s),str_correct))","published":true,"deleted":false,"likes_count":3,"comments_count":1,"created_by":639,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":218,"test_suite_updated_at":"2016-12-12T18:20:56.000Z","rescore_all_solutions":false,"group_id":14,"created_at":"2012-05-14T08:06:55.000Z","updated_at":"2026-03-13T16:25:53.000Z","published_at":"2012-05-14T08:06:55.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eConvert the contents of each fields into a string.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample with an input structure s with 2 fields :\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[s.age = '33'\\ns.prenom ='aurélien']]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe output will be the string of size 1*11 :\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[str =\\n\\n33\\naurélien]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ewhich is the same of typing str = ['33',10,'aurélien']\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":781,"title":"Access a web hosted copy of the Tiles Contest MAT file","description":"Access a web hosted copy of the Tiles Contest sample \"mat\" and verify success by returning for a board the number of tiles, number of rows, and number of columns of the board.\r\n\r\nDetails of the Tiles Contest can be found at \u003chttp://www.mathworks.com/matlabcentral/contest/contests/36 Tiles Contest\u003e.\r\n\r\nThe runcontest.m provides testsuite structure information.\r\n\r\n*Input:* (urlfname, board)\r\n\r\nfn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u00266cq_kc2=yae1d8\u00266cq_konmpb=y88ayxyx8xxy1xdyx'\r\n\r\n*Output:* (number of tiles, nrows, ncols)\r\n\r\nFor board 99\r\n\r\n[ 20 10 8 ]\r\n\r\n\r\n\r\nNote: The mat file is a very efficiently packed binary file.\r\n\r\nFollow-up questions will be creation of a mat file and a timed contest for a few of the perfectly solveable Tile boards","description_html":"\u003cp\u003eAccess a web hosted copy of the Tiles Contest sample \"mat\" and verify success by returning for a board the number of tiles, number of rows, and number of columns of the board.\u003c/p\u003e\u003cp\u003eDetails of the Tiles Contest can be found at \u003ca href=\"http://www.mathworks.com/matlabcentral/contest/contests/36\"\u003eTiles Contest\u003c/a\u003e.\u003c/p\u003e\u003cp\u003eThe runcontest.m provides testsuite structure information.\u003c/p\u003e\u003cp\u003e\u003cb\u003eInput:\u003c/b\u003e (urlfname, board)\u003c/p\u003e\u003cp\u003efn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u00266cq_kc2=yae1d8\u00266cq_konmpb=y88ayxyx8xxy1xdyx'\u003c/p\u003e\u003cp\u003e\u003cb\u003eOutput:\u003c/b\u003e (number of tiles, nrows, ncols)\u003c/p\u003e\u003cp\u003eFor board 99\u003c/p\u003e\u003cp\u003e[ 20 10 8 ]\u003c/p\u003e\u003cp\u003eNote: The mat file is a very efficiently packed binary file.\u003c/p\u003e\u003cp\u003eFollow-up questions will be creation of a mat file and a timed contest for a few of the perfectly solveable Tile boards\u003c/p\u003e","function_template":"function out = access_url_mat(urlfname,brd)\r\n \r\n %tiles=tests.testsuite(brd).tiles;\r\n\r\n ntiles=1;nrow=1;ncol=1;\r\n \r\n out=[ntiles nrow ncol];\r\n\r\nend","test_suite":"%%\r\n% Cody External accessibility\r\ny=clock;\r\nrand('state',floor(10000*y(6)))\r\nbrd=randi(100,1)\r\n\r\nfn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u00266cq_kc2=yae1d8\u00266cq_konmpb=y88ayxyx8xxy1xdyx';\r\n\r\nfn='http://tinyurl.com/matlab-tiles-mat';\r\ntestSuiteFile = 'raz_tiles.mat';\r\nurlwrite(fn,testSuiteFile);\r\n\r\ntests = load(testSuiteFile,'testsuite');\r\n\r\ntiles = tests.testsuite(brd).tiles;\r\nrows = tests.testsuite(brd).r;\r\ncols = tests.testsuite(brd).c;\r\n\r\nexpected=[size(tiles,1) rows cols]\r\n\r\nout=access_url_mat(fn,brd)\r\n\r\nassert(isequal(out,expected))\r\n%%\r\nbrd=randi(100,1)\r\n\r\nfn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u00266cq_kc2=yae1d8\u00266cq_konmpb=y88ayxyx8xxy1xdyx';\r\n\r\nfn='http://tinyurl.com/matlab-tiles-mat';\r\ntestSuiteFile = 'raz_tiles.mat';\r\nurlwrite(fn,testSuiteFile);\r\n\r\ntests = load(testSuiteFile,'testsuite');\r\n\r\ntiles = tests.testsuite(brd).tiles;\r\nrows = tests.testsuite(brd).r;\r\ncols = tests.testsuite(brd).c;\r\n\r\nexpected=[size(tiles,1) rows cols]\r\n\r\nout=access_url_mat(fn,brd)\r\n\r\nassert(isequal(out,expected))\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":2,"created_by":3097,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":7,"test_suite_updated_at":"2012-11-22T12:22:58.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2012-06-21T04:54:17.000Z","updated_at":"2025-10-25T08:50:10.000Z","published_at":"2012-06-22T04:40:01.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eAccess a web hosted copy of the Tiles Contest sample \\\"mat\\\" and verify success by returning for a board the number of tiles, number of rows, and number of columns of the board.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDetails of the Tiles Contest can be found at\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/contest/contests/36\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eTiles Contest\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe runcontest.m provides testsuite structure information.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eInput:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e (urlfname, board)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003efn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u0026amp;6cq_kc2=yae1d8\u0026amp;6cq_konmpb=y88ayxyx8xxy1xdyx'\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eOutput:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e (number of tiles, nrows, ncols)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor board 99\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e[ 20 10 8 ]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eNote: The mat file is a very efficiently packed binary file.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFollow-up questions will be creation of a mat file and a timed contest for a few of the perfectly solveable Tile boards\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":767,"title":"Assign numerical values to a structure with 1 field","description":"The aim is to assign values to a multidimensional structure  *without using for-loop or while-loop*\r\n\r\nExample with a structure 2*3:\r\n\r\n  s = repmat(struct('prices', 0), 2, 3);\r\n  data = [11 12 13 ;21 22 23 ];\r\n\r\nThe expected output s2 will be the following structure 2*3:\r\n\r\n   s2(1,1).prices = 11\r\n   s2(1,2).prices = 12\r\n   s2(1,3).prices = 13\r\n   s2(2,1).prices = 21 \r\n   s2(2,2).prices = 22\r\n   s2(2,3).prices = 23\r\n\r\nRules:\r\n\r\n1) Using For-loops or While-loops is prohibited \r\n\r\n2) For this problem the structure will always have *a single field*. In the above example s has an unique field \"prices\". \r\n\r\n3) However the *name of this field can be changed*\r\n\r\nHave fun!","description_html":"\u003cp\u003eThe aim is to assign values to a multidimensional structure  \u003cb\u003ewithout using for-loop or while-loop\u003c/b\u003e\u003c/p\u003e\u003cp\u003eExample with a structure 2*3:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003es = repmat(struct('prices', 0), 2, 3);\r\ndata = [11 12 13 ;21 22 23 ];\r\n\u003c/pre\u003e\u003cp\u003eThe expected output s2 will be the following structure 2*3:\u003c/p\u003e\u003cpre\u003e   s2(1,1).prices = 11\r\n   s2(1,2).prices = 12\r\n   s2(1,3).prices = 13\r\n   s2(2,1).prices = 21 \r\n   s2(2,2).prices = 22\r\n   s2(2,3).prices = 23\u003c/pre\u003e\u003cp\u003eRules:\u003c/p\u003e\u003cp\u003e1) Using For-loops or While-loops is prohibited\u003c/p\u003e\u003cp\u003e2) For this problem the structure will always have \u003cb\u003ea single field\u003c/b\u003e. In the above example s has an unique field \"prices\".\u003c/p\u003e\u003cp\u003e3) However the \u003cb\u003ename of this field can be changed\u003c/b\u003e\u003c/p\u003e\u003cp\u003eHave fun!\u003c/p\u003e","function_template":"function s2= assign_struct(s,data)\r\n s2 = data;\r\nend","test_suite":"%%\r\ns = repmat(struct('prices', 0), 2, 3);\r\ndata = [11 12 13 ;21 22 23 ];\r\n\r\n% solution\r\n s2(1,1).prices = 11\r\n s2(1,2).prices = 12\r\n s2(1,3).prices = 13\r\n s2(2,1).prices = 21 \r\n s2(2,2).prices = 22\r\n s2(2,3).prices = 23\r\nassert(isequal(assign_struct(s,data),s2))\r\n\r\n% prevents cheating\r\nfiletext = fileread('assign_struct.m')\r\n assert(isempty(strfind(filetext, 'for')))\r\n assert(isempty(strfind(filetext, 'while')))\r\n\r\n%% Another fieldname\r\ns = repmat(struct('yo', 0), 2, 3);\r\ndata = [14 12 13 ;87 22 2.3 ];\r\n\r\n% solution\r\n s2(1,1).yo = 14\r\n s2(1,2).yo = 12\r\n s2(1,3).yo = 13\r\n s2(2,1).yo = 87 \r\n s2(2,2).yo = 22\r\n s2(2,3).yo = 2.3\r\nassert(isequal(assign_struct(s,data),s2))\r\n\r\n% prevents cheating\r\nfiletext = fileread('assign_struct.m')\r\n assert(isempty(strfind(filetext, 'for')))\r\n assert(isempty(strfind(filetext, 'while')))\r\n\r\n%% structure bigger with a random matrix\r\ns = repmat(struct('french', 0), 4, 4);\r\ndata = rand(4);\r\n\r\nfor i = 1:4\r\n      for j = 1:4\r\n          s2(i,j).french = data(i,j);\r\n      end\r\nend\r\nassert(isequal(assign_struct(s,data),s2))\r\n\r\n\r\n% prevents cheating\r\nfiletext = fileread('assign_struct.m')\r\n assert(isempty(strfind(filetext, 'for')))\r\n assert(isempty(strfind(filetext, 'while')))","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":639,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":34,"test_suite_updated_at":"2012-06-15T12:32:22.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2012-06-15T09:08:05.000Z","updated_at":"2025-12-09T17:36:19.000Z","published_at":"2012-06-15T09:08:05.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe aim is to assign values to a multidimensional structure \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ewithout using for-loop or while-loop\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample with a structure 2*3:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[s = repmat(struct('prices', 0), 2, 3);\\ndata = [11 12 13 ;21 22 23 ];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe expected output s2 will be the following structure 2*3:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[   s2(1,1).prices = 11\\n   s2(1,2).prices = 12\\n   s2(1,3).prices = 13\\n   s2(2,1).prices = 21 \\n   s2(2,2).prices = 22\\n   s2(2,3).prices = 23]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eRules:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e1) Using For-loops or While-loops is prohibited\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e2) For this problem the structure will always have\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ea single field\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e. In the above example s has an unique field \\\"prices\\\".\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e3) However the\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ename of this field can be changed\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHave fun!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":43685,"title":"Apply Function to Each Field of a Structure Array: Part 1","description":"The builtin \u003chttp://www.mathworks.com/help/matlab/ref/structfun.html?=structfun structfun\u003e applies a function handle to each field of a *scalar structure*, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\r\n\r\nWrite your own function *structfun2* which accepts a structure array *s* and a function handle *f* as the inputs. The output *c = structfun2(f,s)* is a cell array of the same size as *s*, with each cell storing the result of *f* applied to every field of the relevant structure element in *s*. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, structfun2(f,s) = structfun(f,s) holds for any scalar structure *s*. The assumption required is that *f* is a function that returns a scalar, regardless of the input. \r\n\r\nExample: \r\n\r\n  s = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\n  f = @numel;\r\n  c = {[1;2], [2;1]; [1;3], [2;2]};\r\n\r\nRelated problems in this series:\r\n\r\n* \u003chttp://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2 Apply Function to Each Field of a Structure Array: Part 2\u003e\r\n* \u003chttp://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1 Apply Function to Each Field of a Structure Array: Part 1\u003e","description_html":"\u003cp\u003eThe builtin \u003ca href = \"http://www.mathworks.com/help/matlab/ref/structfun.html?=structfun\"\u003estructfun\u003c/a\u003e applies a function handle to each field of a \u003cb\u003escalar structure\u003c/b\u003e, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\u003c/p\u003e\u003cp\u003eWrite your own function \u003cb\u003estructfun2\u003c/b\u003e which accepts a structure array \u003cb\u003es\u003c/b\u003e and a function handle \u003cb\u003ef\u003c/b\u003e as the inputs. The output \u003cb\u003ec = structfun2(f,s)\u003c/b\u003e is a cell array of the same size as \u003cb\u003es\u003c/b\u003e, with each cell storing the result of \u003cb\u003ef\u003c/b\u003e applied to every field of the relevant structure element in \u003cb\u003es\u003c/b\u003e. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, structfun2(f,s) = structfun(f,s) holds for any scalar structure \u003cb\u003es\u003c/b\u003e. The assumption required is that \u003cb\u003ef\u003c/b\u003e is a function that returns a scalar, regardless of the input.\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003es = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\nf = @numel;\r\nc = {[1;2], [2;1]; [1;3], [2;2]};\r\n\u003c/pre\u003e\u003cp\u003eRelated problems in this series:\u003c/p\u003e\u003cul\u003e\u003cli\u003e\u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2\"\u003eApply Function to Each Field of a Structure Array: Part 2\u003c/a\u003e\u003c/li\u003e\u003cli\u003e\u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1\"\u003eApply Function to Each Field of a Structure Array: Part 1\u003c/a\u003e\u003c/li\u003e\u003c/ul\u003e","function_template":"function y = structfun2(f,s)\r\n  y = x;\r\nend","test_suite":"%%\r\ns.f1 = 'Sunday';\r\ns.f2 = 'Monday';\r\ns.f3 = 'Tuesday'; \r\ns.f4 = 'Wednesday';\r\ns.f5 = 'Thursday';\r\ns.f6 = 'Friday';\r\ns.f7 = 'Saturday';\r\nf = @numel;\r\nc = structfun(@numel, s);\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\nf = @(x)min(x(:));\r\nc = {[1;1], [3;2]; [1;3], [5;2]};\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\nf = @(x)max(x(:));\r\nc = {[1;2], [4;2]; [1;5], [6;5]};\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{0, [3 4]; 1, [5 7 6]},'f2',{[0 0], 2; [2 4 5], [0 5]});\r\nf = @nnz;\r\nc = {[0;0], [2;1]; [1;3], [3;1]};\r\nassert(isequal(structfun2(f,s),c))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":12569,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":31,"test_suite_updated_at":"2016-12-01T22:39:09.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2016-11-27T01:04:06.000Z","updated_at":"2025-12-14T11:39:11.000Z","published_at":"2016-11-27T01:32:39.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe builtin\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/help/matlab/ref/structfun.html?=structfun\\\"\u003e\u003cw:r\u003e\u003cw:t\u003estructfun\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e applies a function handle to each field of a\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003escalar structure\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eWrite your own function\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003estructfun2\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e which accepts a structure array\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e and a function handle\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e as the inputs. The output\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ec = structfun2(f,s)\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is a cell array of the same size as\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e, with each cell storing the result of\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e applied to every field of the relevant structure element in\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, structfun2(f,s) = structfun(f,s) holds for any scalar structure\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e. The assumption required is that\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is a function that returns a scalar, regardless of the input.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[s = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\\nf = @numel;\\nc = {[1;2], [2;1]; [1;3], [2;2]};]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eRelated problems in this series:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eApply Function to Each Field of a Structure Array: Part 2\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eApply Function to Each Field of a Structure Array: Part 1\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":689,"title":"Sort an array of structures","description":"You need to sort an array of structures based upon *a numeric first field*:\r\n\r\nFor example :\r\n\r\n  a.n=1;\r\n  a.name='a';\r\n  b.n=3;\r\n  b.name='b';\r\n  c.n=2;\r\n  c.name='c';\r\n  array = [a b c]\r\n\r\nThis array of 3 structures is not sorted yet since:\r\n\r\n  \u003e\u003e array(2)\r\n\r\nshows:\r\nans = \r\n\r\n       n: 3\r\n    name: 'b'\r\n\r\nThe aim is to have for this example the output _array_ such as :\r\n\r\n  \u003e\u003e array(1)\r\n  \r\n  ans = \r\n  \r\n         n: 1\r\n      name: 'a'\r\n  \r\n  \u003e\u003e array(2)\r\n  \r\n  ans = \r\n  \r\n         n: 2\r\n      name: 'c'\r\n  \r\n  \u003e\u003e array(3)\r\n  \r\n  ans = \r\n  \r\n         n: 3\r\n      name: 'b'\r\n  \r\n\r\nThe input of this problem is an array of structures. .","description_html":"\u003cp\u003eYou need to sort an array of structures based upon \u003cb\u003ea numeric first field\u003c/b\u003e:\u003c/p\u003e\u003cp\u003eFor example :\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003ea.n=1;\r\na.name='a';\r\nb.n=3;\r\nb.name='b';\r\nc.n=2;\r\nc.name='c';\r\narray = [a b c]\r\n\u003c/pre\u003e\u003cp\u003eThis array of 3 structures is not sorted yet since:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003e\u003e\u003e array(2)\r\n\u003c/pre\u003e\u003cp\u003eshows:\r\nans =\u003c/p\u003e\u003cpre\u003e       n: 3\r\n    name: 'b'\u003c/pre\u003e\u003cp\u003eThe aim is to have for this example the output \u003ci\u003earray\u003c/i\u003e such as :\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003e\u003e\u003e array(1)\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003eans = \r\n\u003c/pre\u003e\u003cpre\u003e         n: 1\r\n      name: 'a'\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e\u003e\u003e array(2)\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003eans = \r\n\u003c/pre\u003e\u003cpre\u003e         n: 2\r\n      name: 'c'\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e\u003e\u003e array(3)\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003eans = \r\n\u003c/pre\u003e\u003cpre\u003e         n: 3\r\n      name: 'b'\u003c/pre\u003e\u003cp\u003eThe input of this problem is an array of structures. .\u003c/p\u003e","function_template":"function array_sorted = your_fcn_name(array)\r\n  array_correct  = array;\r\nend","test_suite":"%% Test the example\r\na.n=1;\r\na.name='a';\r\nb.n=3;\r\nb.name='b';\r\nc.n=2;\r\nc.name='c';\r\narray = [a b c]\r\n\r\n% solution based on the first numeric field :\r\narray_sorted = [a c b]\r\n\r\nassert(isequal(your_fcn_name(array),array_sorted))\r\n\r\n%% Another test\r\ns1.age = 33\r\ns1.name = 'aurelien'\r\ns2.age = 25\r\ns2.name = 'jeanpierre'\r\narray = [s1 s2 ]\r\n\r\n% solution based on the first numeric field :\r\narray_sorted = [s2 s1]\r\n\r\nassert(isequal(your_fcn_name(array),array_sorted))","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":639,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":49,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2012-05-14T08:20:20.000Z","updated_at":"2025-12-07T19:33:55.000Z","published_at":"2012-05-14T08:20:20.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou need to sort an array of structures based upon\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ea numeric first field\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example :\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[a.n=1;\\na.name='a';\\nb.n=3;\\nb.name='b';\\nc.n=2;\\nc.name='c';\\narray = [a b c]]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThis array of 3 structures is not sorted yet since:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[\u003e\u003e array(2)]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eshows: ans =\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[       n: 3\\n    name: 'b']]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe aim is to have for this example the output\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003earray\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e such as :\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[\u003e\u003e array(1)\\n\\nans = \\n\\n         n: 1\\n      name: 'a'\\n\\n\u003e\u003e array(2)\\n\\nans = \\n\\n         n: 2\\n      name: 'c'\\n\\n\u003e\u003e array(3)\\n\\nans = \\n\\n         n: 3\\n      name: 'b']]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe input of this problem is an array of structures. .\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":43686,"title":"Apply Function to Each Field of a Structure Array: Part 2","description":"The builtin \u003chttp://www.mathworks.com/help/matlab/ref/structfun.html?=structfun structfun\u003e applies a function handle to each field of a *scalar structure*, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\r\n\r\nWrite your own function *structfun2* which accepts a structure array *s* and a function handle *f* as the inputs. The output *c = structfun2(f,s)* is a structure array *c* of the same size and same fields as *s*, where each field of the structure element of c stores the result of *f* applied to the same field of the relevant structure element in *s*. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, when *s* is a scalar structure, your output reduces to c = structfun(f,s,'UniformOutput',false). No assumption on *f* is needed in this problem. \r\n \r\n\r\nExample: \r\n\r\n  s = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\n  f = @numel;\r\n  c = struct('f1',{1, 2; 1, 2},'f2',{2, 1; 3, 2});\r\n\r\nRelated problems in this series:\r\n\r\n* \u003chttp://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1 Apply Function to Each Field of a Structure Array: Part 1\u003e\r\n* \u003chttp://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2 Apply Function to Each Field of a Structure Array: Part 2\u003e\r\n","description_html":"\u003cp\u003eThe builtin \u003ca href = \"http://www.mathworks.com/help/matlab/ref/structfun.html?=structfun\"\u003estructfun\u003c/a\u003e applies a function handle to each field of a \u003cb\u003escalar structure\u003c/b\u003e, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\u003c/p\u003e\u003cp\u003eWrite your own function \u003cb\u003estructfun2\u003c/b\u003e which accepts a structure array \u003cb\u003es\u003c/b\u003e and a function handle \u003cb\u003ef\u003c/b\u003e as the inputs. The output \u003cb\u003ec = structfun2(f,s)\u003c/b\u003e is a structure array \u003cb\u003ec\u003c/b\u003e of the same size and same fields as \u003cb\u003es\u003c/b\u003e, where each field of the structure element of c stores the result of \u003cb\u003ef\u003c/b\u003e applied to the same field of the relevant structure element in \u003cb\u003es\u003c/b\u003e. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, when \u003cb\u003es\u003c/b\u003e is a scalar structure, your output reduces to c = structfun(f,s,'UniformOutput',false). No assumption on \u003cb\u003ef\u003c/b\u003e is needed in this problem.\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003es = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\r\nf = @numel;\r\nc = struct('f1',{1, 2; 1, 2},'f2',{2, 1; 3, 2});\r\n\u003c/pre\u003e\u003cp\u003eRelated problems in this series:\u003c/p\u003e\u003cul\u003e\u003cli\u003e\u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1\"\u003eApply Function to Each Field of a Structure Array: Part 1\u003c/a\u003e\u003c/li\u003e\u003cli\u003e\u003ca href = \"http://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2\"\u003eApply Function to Each Field of a Structure Array: Part 2\u003c/a\u003e\u003c/li\u003e\u003c/ul\u003e","function_template":"function y = structfun2(f,s)\r\n  y = s;\r\nend","test_suite":"%%\r\ns.f1 = 'Sunday';\r\ns.f2 = 'Monday';\r\ns.f3 = 'Tuesday'; \r\ns.f4 = 'Wednesday';\r\ns.f5 = 'Thursday';\r\ns.f6 = 'Friday';\r\ns.f7 = 'Saturday';\r\nf = @(x)x(1:3);\r\nc = structfun(f,s,'UniformOutput',false);\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4;5 6]; 1, [5 6;7 8]},'f2',{[1 2], 2; [3 4 5;6 7 8], [2 6;4 5]});\r\nf = @min;\r\nc = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{1, 2; [3 4 5], [2 5]});\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4;5 6]; 1, [5 6;7 8]},'f2',{[1 2], 2; [3 4 5;6 7 8], [2 6;4 5]});\r\nf = @sum;\r\nc = struct('f1',{1, [8 10]; 1, [12 14]},'f2',{3, 2; [9 11 13], [6 11]});\r\nassert(isequal(structfun2(f,s),c))\r\n\r\n%%\r\ns = struct('f1',{1, [3 4;5 6]; 1, [5 6;7 8]},'f2',{[1 2], 2; [3 4 5;6 7 8], [2 6;4 5]});\r\nf = @pow2;\r\nc = struct('f1',{2, [8 16;32 64]; 2, [32 64;128 256]},'f2',{[2 4], 4; [8 16 32;64 128 256], [4 64;16 32]});\r\nassert(isequal(structfun2(f,s),c))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":1,"created_by":12569,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":24,"test_suite_updated_at":"2016-12-01T22:27:07.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2016-11-27T02:12:26.000Z","updated_at":"2025-12-15T21:01:07.000Z","published_at":"2016-11-27T02:12:31.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe builtin\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/help/matlab/ref/structfun.html?=structfun\\\"\u003e\u003cw:r\u003e\u003cw:t\u003estructfun\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e applies a function handle to each field of a\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003escalar structure\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e, but it does not work for structure array. The purpose of this problem is to generalize structfun to enable support for structure array input.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eWrite your own function\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003estructfun2\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e which accepts a structure array\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e and a function handle\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e as the inputs. The output\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ec = structfun2(f,s)\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is a structure array\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ec\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e of the same size and same fields as\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e, where each field of the structure element of c stores the result of\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e applied to the same field of the relevant structure element in\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e. The structfun2 must preserve the behavior of structfun for scalar structure input. That is, when\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003es\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is a scalar structure, your output reduces to c = structfun(f,s,'UniformOutput',false). No assumption on\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ef\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e is needed in this problem.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[s = struct('f1',{1, [3 4]; 1, [5 6]},'f2',{[1 2], 2; [3 4 5], [2 5]});\\nf = @numel;\\nc = struct('f1',{1, 2; 1, 2},'f2',{2, 1; 3, 2});]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eRelated problems in this series:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/43685-apply-function-to-each-field-of-a-structure-array-part-1\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eApply Function to Each Field of a Structure Array: Part 1\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/cody/problems/43686-apply-function-to-each-field-of-a-structure-array-part-2\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eApply Function to Each Field of a Structure Array: Part 2\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":688,"title":"Convert a structure into a string","description":"Convert the contents of each fields into a string.\r\n\r\nExample with an input structure s with 2 fields : \r\n\r\n  s.age = '33'\r\n  s.prenom ='aurélien'\r\n  \r\nThe output will be the string of size 1*11 :\r\n\r\n  str =\r\n  \r\n  33\r\n  aurélien\r\n\r\nwhich is the same of typing str = ['33',10,'aurélien']","description_html":"\u003cp\u003eConvert the contents of each fields into a string.\u003c/p\u003e\u003cp\u003eExample with an input structure s with 2 fields :\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003es.age = '33'\r\ns.prenom ='aurélien'\r\n\u003c/pre\u003e\u003cp\u003eThe output will be the string of size 1*11 :\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003estr =\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e33\r\naurélien\r\n\u003c/pre\u003e\u003cp\u003ewhich is the same of typing str = ['33',10,'aurélien']\u003c/p\u003e","function_template":"function str = your_fcn_name(s)\r\n  y = x;\r\nend","test_suite":"%%\r\ns.age = '33'\r\ns.prenom ='aurélien'\r\nstr_correct = ['33',10,'aurélien'];\r\nassert(isequal(your_fcn_name(s),str_correct))\r\n\r\n%%\r\ns.f1 = 'Sunday'; \r\ns.f2 = 'Monday'; \r\ns.f3 = 'Tuesday';\r\ns.f4 = 'Wednesday'; \r\ns.f5 = 'Thursday'; \r\ns.f6 = 'Friday';\r\ns.f7 = 'Saturday';\r\nstr_correct = ['Sunday',10,'Monday',10,'Tuesday',10,'Wednesday',10,'Thursday',10,'Friday',10,'Saturday'];\r\nassert(isequal(your_fcn_name(s),str_correct))\r\n\r\n%%\r\ns.age = '42';\r\ns.height = '73.5';\r\ns.weight = '173';\r\nstr_correct = ['42',10,'73.5',10,'173'];\r\nassert(isequal(your_fcn_name(s),str_correct))\r\n\r\n%%\r\ns.hair = 'brown';\r\ns.eye = 'green';\r\ns.fav = 'gold';\r\nstr_correct = ['brown',10,'green',10,'gold'];\r\nassert(isequal(your_fcn_name(s),str_correct))\r\n\r\n%%\r\ns.first = 'Tom';\r\ns.second = 'Jeff';\r\ns.third = 'Bill';\r\ns.fourth = 'Jerry';\r\ns.fifth = 'Harold';\r\nstr_correct = ['Tom',10,'Jeff',10,'Bill',10,'Jerry',10,'Harold'];\r\nassert(isequal(your_fcn_name(s),str_correct))","published":true,"deleted":false,"likes_count":3,"comments_count":1,"created_by":639,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":218,"test_suite_updated_at":"2016-12-12T18:20:56.000Z","rescore_all_solutions":false,"group_id":14,"created_at":"2012-05-14T08:06:55.000Z","updated_at":"2026-03-13T16:25:53.000Z","published_at":"2012-05-14T08:06:55.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eConvert the contents of each fields into a string.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample with an input structure s with 2 fields :\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[s.age = '33'\\ns.prenom ='aurélien']]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe output will be the string of size 1*11 :\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[str =\\n\\n33\\naurélien]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ewhich is the same of typing str = ['33',10,'aurélien']\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":781,"title":"Access a web hosted copy of the Tiles Contest MAT file","description":"Access a web hosted copy of the Tiles Contest sample \"mat\" and verify success by returning for a board the number of tiles, number of rows, and number of columns of the board.\r\n\r\nDetails of the Tiles Contest can be found at \u003chttp://www.mathworks.com/matlabcentral/contest/contests/36 Tiles Contest\u003e.\r\n\r\nThe runcontest.m provides testsuite structure information.\r\n\r\n*Input:* (urlfname, board)\r\n\r\nfn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u00266cq_kc2=yae1d8\u00266cq_konmpb=y88ayxyx8xxy1xdyx'\r\n\r\n*Output:* (number of tiles, nrows, ncols)\r\n\r\nFor board 99\r\n\r\n[ 20 10 8 ]\r\n\r\n\r\n\r\nNote: The mat file is a very efficiently packed binary file.\r\n\r\nFollow-up questions will be creation of a mat file and a timed contest for a few of the perfectly solveable Tile boards","description_html":"\u003cp\u003eAccess a web hosted copy of the Tiles Contest sample \"mat\" and verify success by returning for a board the number of tiles, number of rows, and number of columns of the board.\u003c/p\u003e\u003cp\u003eDetails of the Tiles Contest can be found at \u003ca href=\"http://www.mathworks.com/matlabcentral/contest/contests/36\"\u003eTiles Contest\u003c/a\u003e.\u003c/p\u003e\u003cp\u003eThe runcontest.m provides testsuite structure information.\u003c/p\u003e\u003cp\u003e\u003cb\u003eInput:\u003c/b\u003e (urlfname, board)\u003c/p\u003e\u003cp\u003efn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u00266cq_kc2=yae1d8\u00266cq_konmpb=y88ayxyx8xxy1xdyx'\u003c/p\u003e\u003cp\u003e\u003cb\u003eOutput:\u003c/b\u003e (number of tiles, nrows, ncols)\u003c/p\u003e\u003cp\u003eFor board 99\u003c/p\u003e\u003cp\u003e[ 20 10 8 ]\u003c/p\u003e\u003cp\u003eNote: The mat file is a very efficiently packed binary file.\u003c/p\u003e\u003cp\u003eFollow-up questions will be creation of a mat file and a timed contest for a few of the perfectly solveable Tile boards\u003c/p\u003e","function_template":"function out = access_url_mat(urlfname,brd)\r\n \r\n %tiles=tests.testsuite(brd).tiles;\r\n\r\n ntiles=1;nrow=1;ncol=1;\r\n \r\n out=[ntiles nrow ncol];\r\n\r\nend","test_suite":"%%\r\n% Cody External accessibility\r\ny=clock;\r\nrand('state',floor(10000*y(6)))\r\nbrd=randi(100,1)\r\n\r\nfn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u00266cq_kc2=yae1d8\u00266cq_konmpb=y88ayxyx8xxy1xdyx';\r\n\r\nfn='http://tinyurl.com/matlab-tiles-mat';\r\ntestSuiteFile = 'raz_tiles.mat';\r\nurlwrite(fn,testSuiteFile);\r\n\r\ntests = load(testSuiteFile,'testsuite');\r\n\r\ntiles = tests.testsuite(brd).tiles;\r\nrows = tests.testsuite(brd).r;\r\ncols = tests.testsuite(brd).c;\r\n\r\nexpected=[size(tiles,1) rows cols]\r\n\r\nout=access_url_mat(fn,brd)\r\n\r\nassert(isequal(out,expected))\r\n%%\r\nbrd=randi(100,1)\r\n\r\nfn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u00266cq_kc2=yae1d8\u00266cq_konmpb=y88ayxyx8xxy1xdyx';\r\n\r\nfn='http://tinyurl.com/matlab-tiles-mat';\r\ntestSuiteFile = 'raz_tiles.mat';\r\nurlwrite(fn,testSuiteFile);\r\n\r\ntests = load(testSuiteFile,'testsuite');\r\n\r\ntiles = tests.testsuite(brd).tiles;\r\nrows = tests.testsuite(brd).r;\r\ncols = tests.testsuite(brd).c;\r\n\r\nexpected=[size(tiles,1) rows cols]\r\n\r\nout=access_url_mat(fn,brd)\r\n\r\nassert(isequal(out,expected))\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":2,"created_by":3097,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":7,"test_suite_updated_at":"2012-11-22T12:22:58.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2012-06-21T04:54:17.000Z","updated_at":"2025-10-25T08:50:10.000Z","published_at":"2012-06-22T04:40:01.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eAccess a web hosted copy of the Tiles Contest sample \\\"mat\\\" and verify success by returning for a board the number of tiles, number of rows, and number of columns of the board.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDetails of the Tiles Contest can be found at\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://www.mathworks.com/matlabcentral/contest/contests/36\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eTiles Contest\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe runcontest.m provides testsuite structure information.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eInput:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e (urlfname, board)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003efn='http://www.toobigforemail.com/cryptkeeper.toobig?nppmkc2=xyeffg\u0026amp;6cq_kc2=yae1d8\u0026amp;6cq_konmpb=y88ayxyx8xxy1xdyx'\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eOutput:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e (number of tiles, nrows, ncols)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor board 99\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e[ 20 10 8 ]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eNote: The mat file is a very efficiently packed binary file.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFollow-up questions will be creation of a mat file and a timed contest for a few of the perfectly solveable Tile boards\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray 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