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Question
4th order runge-kutta method to solve two 1st order differential equations
%%4th order runge-kutta for Project 2 fy=@(t,y,z) z; fz=@(t,y,z) (36000/(1500-40*t))-9.81-((0.1962*z^2)/(1500-40*t)); %boun...
2 years ago | 1 answer | 0