Answered

Convert a vector to single element

signal = dec2bin((0:255)'); or fullfact([2 2 2 2 2 2 2]) - 1; in your case for i = 256:-1:1 signal(i,:) = dec2bin(i-1,...

Convert a vector to single element

signal = dec2bin((0:255)'); or fullfact([2 2 2 2 2 2 2]) - 1; in your case for i = 256:-1:1 signal(i,:) = dec2bin(i-1,...

1 year ago | 1

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Answered

Extracting a vector from elements of a matrices that are in a cell structure.

V = cat(1,C{:}); V(:,1)' V(:,2)'

Extracting a vector from elements of a matrices that are in a cell structure.

V = cat(1,C{:}); V(:,1)' V(:,2)'

1 year ago | 0

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Answered

converting a matrix sequentially in to single column

Let A - your array. k = 30; [m,n] = size(A); out = reshape(permute(reshape(A,k,[],n),[1,3,2]),[],n);

converting a matrix sequentially in to single column

Let A - your array. k = 30; [m,n] = size(A); out = reshape(permute(reshape(A,k,[],n),[1,3,2]),[],n);

1 year ago | 0

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Answered

How to convert datenum to datetime in a MATLAB Table

a=[2 737735.191331019 6 737735.182129630 3 737735.182013889 7 737735.141481482]; T...

How to convert datenum to datetime in a MATLAB Table

a=[2 737735.191331019 6 737735.182129630 3 737735.182013889 7 737735.141481482]; T...

1 year ago | 0

Answered

Unique Number Assignment To Each Time

a=[1.1, 1.1, 1.1, 1.2, 1.2, 1.2, 2.1, 2.1, 2.1]' [i,g]=findgroups(a); out = i - 1;

Unique Number Assignment To Each Time

a=[1.1, 1.1, 1.1, 1.2, 1.2, 1.2, 2.1, 2.1, 2.1]' [i,g]=findgroups(a); out = i - 1;

1 year ago | 0

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Answered

Find max value with multiple conditions

T=readtable('wave height data.xlsx'); [r,rn] = findgroups(T(:,1)); [c,cn] = findgroups(T(:,2)); out = accumarray([r,c],T.Wave...

Find max value with multiple conditions

T=readtable('wave height data.xlsx'); [r,rn] = findgroups(T(:,1)); [c,cn] = findgroups(T(:,2)); out = accumarray([r,c],T.Wave...

1 year ago | 1

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Answered

Count smaller than 15 cells in the table coulumns

T = varfun(@funir,results_excel,'I',2:5); T.Properties.VariableNames = results_excel.Properties.VariableNames(2:end); T.statio...

Count smaller than 15 cells in the table coulumns

T = varfun(@funir,results_excel,'I',2:5); T.Properties.VariableNames = results_excel.Properties.VariableNames(2:end); T.statio...

1 year ago | 1

Answered

Is there a way to find the max value in an array without using the "max" command?

Let A - your array. B = A(:); max_value = B(all(B - B' <= 0));

Is there a way to find the max value in an array without using the "max" command?

Let A - your array. B = A(:); max_value = B(all(B - B' <= 0));

1 year ago | 0

Answered

how can i find the average of every single raw in a matrix without using sum or mean function ?

n = size(sc,2); out = sc*ones(n,1)/n;

how can i find the average of every single raw in a matrix without using sum or mean function ?

n = size(sc,2); out = sc*ones(n,1)/n;

1 year ago | 0

Answered

Consolidating counts & sum by Year Range

y = [2001, 2002, 2005 2003, 2004, 2007]; A = [2001 2002 2001 2003 2003 2003 2004 2004 2004 2004 2004 2007; 1 ...

Consolidating counts & sum by Year Range

y = [2001, 2002, 2005 2003, 2004, 2007]; A = [2001 2002 2001 2003 2003 2003 2004 2004 2004 2004 2004 2007; 1 ...

1 year ago | 1

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Answered

Convert Columns Arrays to numeric

...how can I know the data type of the columns? varfun(@class,combine) solution: load('data.mat') combine = [combine,rowfu...

Convert Columns Arrays to numeric

...how can I know the data type of the columns? varfun(@class,combine) solution: load('data.mat') combine = [combine,rowfu...

1 year ago | 1

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Answered

Matrix dimensions must agree error in if loop

day = input('What day is today? -> ', 's'); lo = any(strcmpi(day,{'saturday','sunday'})); if lo disp(['Its ' day ' ! ...

Matrix dimensions must agree error in if loop

day = input('What day is today? -> ', 's'); lo = any(strcmpi(day,{'saturday','sunday'})); if lo disp(['Its ' day ' ! ...

1 year ago | 0

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Answered

How to solve the following exercise?

function out = find_neighbor(M,i,j) out = all(ismember(1:M(i,j)-1,M(i-1:i+1,j-1:j+1))); end

How to solve the following exercise?

function out = find_neighbor(M,i,j) out = all(ismember(1:M(i,j)-1,M(i-1:i+1,j-1:j+1))); end

1 year ago | 1

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Answered

Collect matrix values by using a "for" loop

Let A - your array. out = reshape(A.',[],1);

Collect matrix values by using a "for" loop

Let A - your array. out = reshape(A.',[],1);

1 year ago | 0

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Answered

How can I convert 2 column matrix to a cell array?

T = readtable('path\to\your\xls\file\matrix.xlsx','ReadVariableNames',0); T.Var3 = str2double(T.Var3); T = T(any(T{:,1:2} ~= 0...

How can I convert 2 column matrix to a cell array?

T = readtable('path\to\your\xls\file\matrix.xlsx','ReadVariableNames',0); T.Var3 = str2double(T.Var3); T = T(any(T{:,1:2} ~= 0...

1 year ago | 0

Answered

find common elements from cell array and remove it

out = A(~ismember([A{:}],[B{:}]));

find common elements from cell array and remove it

out = A(~ismember([A{:}],[B{:}]));

1 year ago | 0

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Answered

Adding values from columns 1:i for each column for a new matrix of the same size

Let A - your array (442 x 25) out = cumsum(A,2);

Adding values from columns 1:i for each column for a new matrix of the same size

Let A - your array (442 x 25) out = cumsum(A,2);

1 year ago | 0

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Answered

Find the median row of a binary column and replace the column with just the median row

I = imread('line.png'); bw = im2double(rgb2gray(I)); [i,j] = find(bw); [n,g] = findgroups(j); idx = floor(splitapply(@medi...

Find the median row of a binary column and replace the column with just the median row

I = imread('line.png'); bw = im2double(rgb2gray(I)); [i,j] = find(bw); [n,g] = findgroups(j); idx = floor(splitapply(@medi...

1 year ago | 0

Answered

Extracting values from a cell array into new arrays

CC = cat(3,C{:}); [m,n,k] = size(CC); Z = permute(repmat(b,1,1,n),[1,3,2]); out = CC(sub2ind([m,n,k],Z(:,:,2),repmat(1:n,size...

Extracting values from a cell array into new arrays

CC = cat(3,C{:}); [m,n,k] = size(CC); Z = permute(repmat(b,1,1,n),[1,3,2]); out = CC(sub2ind([m,n,k],Z(:,:,2),repmat(1:n,size...

1 year ago | 0

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Answered

How would I create a matrix from the following strings

T = readtable('Path\your\txt\file\ThinPlateNodes.txt'); T.Varend = str2double(regexp(T{:,end},'(\-)?\d+(\.\d+e\-\d+)?(?=\}$)','...

How would I create a matrix from the following strings

T = readtable('Path\your\txt\file\ThinPlateNodes.txt'); T.Varend = str2double(regexp(T{:,end},'(\-)?\d+(\.\d+e\-\d+)?(?=\}$)','...

1 year ago | 1

Answered

Finding Unique values for First Row of a Matrix

Let A - your array. output = A(1,:); for i = 2:numel(output) u = unique([output(1:i-1)';A(:,i)]); output(i) = u(i); ...

Finding Unique values for First Row of a Matrix

Let A - your array. output = A(1,:); for i = 2:numel(output) u = unique([output(1:i-1)';A(:,i)]); output(i) = u(i); ...

1 year ago | 0

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Answered

Index Exceeds Matrix Dimensions

T = readtable('sample.xlsx','ReadVariableNames',0); T.Properties.VariableNames = {'data','Longitude','Lattitude','altitude','De...

Index Exceeds Matrix Dimensions

T = readtable('sample.xlsx','ReadVariableNames',0); T.Properties.VariableNames = {'data','Longitude','Lattitude','altitude','De...

1 year ago | 0

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Answered

Creating a new matrix based on the data from other two matrices

out = reshape([reshape(g1',2,[],2);reshape(g2',3,[],2)],[],2)'

Creating a new matrix based on the data from other two matrices

out = reshape([reshape(g1',2,[],2);reshape(g2',3,[],2)],[],2)'

1 year ago | 1

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Answered

How to normalize a vector considering both maximum and the sum of values?

Please run follow m - file: SN = 8700; Nmx = 9900; nmn = fzero(@(x)func1(x,Nmx,SN,A),-10000); [~,N] = func1(nmn,Nmx,SN,A);...

How to normalize a vector considering both maximum and the sum of values?

Please run follow m - file: SN = 8700; Nmx = 9900; nmn = fzero(@(x)func1(x,Nmx,SN,A),-10000); [~,N] = func1(nmn,Nmx,SN,A);...

1 year ago | 0

Answered

Converting a cell array into a matrix of stipulated number of columns and rows

Let C - your cell array. if cells sizes are the same: out = reshape(cat(2,C{:}),[],4); if not the same: out = cell2mat(cel...

Converting a cell array into a matrix of stipulated number of columns and rows

Let C - your cell array. if cells sizes are the same: out = reshape(cat(2,C{:}),[],4); if not the same: out = cell2mat(cel...

1 year ago | 1

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Answered

how to generate matrix with any size in same pattern

n = 5; out = full(spdiags(ones(n,1)*[1 -2 1],-1:1,n,n)); or out = zeros(n); out([2:n+1:end,n+1:n+1:end]) = 1; out(1:n+1:end...

how to generate matrix with any size in same pattern

n = 5; out = full(spdiags(ones(n,1)*[1 -2 1],-1:1,n,n)); or out = zeros(n); out([2:n+1:end,n+1:n+1:end]) = 1; out(1:n+1:end...

1 year ago | 0

Answered

Mean of certain elements within a matrix

Here A - your array (m x 6) [m,n] = size(A); i = repmat((0:m-1)',1,n-1); i(:,end-1:end) = circshift(i(:,end-1:end),-1); i = ...

Mean of certain elements within a matrix

Here A - your array (m x 6) [m,n] = size(A); i = repmat((0:m-1)',1,n-1); i(:,end-1:end) = circshift(i(:,end-1:end),-1); i = ...

1 year ago | 0

Answered

Use of backslash while calculating the product of inverse of a matrix and another matrix

Maybe for "second way": xt = (D+omg*L)\((D*(1-omg)-omg*U)*xn+omg*((D+omg*L)\B));

Use of backslash while calculating the product of inverse of a matrix and another matrix

Maybe for "second way": xt = (D+omg*L)\((D*(1-omg)-omg*U)*xn+omg*((D+omg*L)\B));

1 year ago | 0

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Answered

How to code this formula?

function rgb = HSVtoRGB(H,S,V) n = numel(H); C = V.*S; X = C .* (1 - abs(mod(H/60,2) - 1)); A = [C, X, zeros...

How to code this formula?

function rgb = HSVtoRGB(H,S,V) n = numel(H); C = V.*S; X = C .* (1 - abs(mod(H/60,2) - 1)); A = [C, X, zeros...

1 year ago | 0