# gaminv

Gamma inverse cumulative distribution function

## Syntax

```X = gaminv(P,A,B) [X,XLO,XUP] = gaminv(P,A,B,pcov,alpha) ```

## Description

`X = gaminv(P,A,B)` computes the inverse of the gamma cdf with shape parameters in `A` and scale parameters in `B` for the corresponding probabilities in `P`. `P`, `A`, and `B` can be vectors, matrices, or multidimensional arrays that all have the same size. A scalar input is expanded to a constant array with the same dimensions as the other inputs. The parameters in `A` and `B` must all be positive, and the values in `P` must lie on the interval `[0 1]`.

The gamma inverse function in terms of the gamma cdf is

`$x={F}^{-1}\left(p|a,b\right)=\left\{x:F\left(x|a,b\right)=p\right\}$`

where

`$p=F\left(x|a,b\right)=\frac{1}{{b}^{a}\Gamma \left(a\right)}\underset{0}{\overset{x}{\int }}{t}^{a-1}{e}^{\frac{-t}{b}}dt$`

`[X,XLO,XUP] = gaminv(P,A,B,pcov,alpha)` produces confidence bounds for `X` when the input parameters `A` and `B` are estimates. `pcov` is a 2-by-2 matrix containing the covariance matrix of the estimated parameters. `alpha` has a default value of 0.05, and specifies `100(1-alpha)`% confidence bounds. `XLO` and `XUP` are arrays of the same size as `X` containing the lower and upper confidence bounds.

## Examples

This example shows the relationship between the gamma cdf and its inverse function.

```a = 1:5; b = 6:10; x = gaminv(gamcdf(1:5,a,b),a,b) x = 1.0000 2.0000 3.0000 4.0000 5.0000```

## Algorithms

There is no known analytical solution to the integral equation above. `gaminv` uses an iterative approach (Newton's method) to converge on the solution.

Download ebook