Calculate percentage of zeros and ones in my vector?

I've already have my vector and number of zeros and ones with this code:

   u=[1 1 1 1 1 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 0 0 0]
   transitions=(find(u~=[u(2:end), u(end)+1]));
   value=u(transitions)
   transitions(2:end)=transitions(2:end)-transitions(1:end-1)

i get this

 value =

 1     0     1     0     1     0

 transitions =

 5     3     2     7     5     3

Now, please if someone could help me and explain how I can get percentage of ones and percentage of zeros in my vector (all together, and by each value). Thank You very much.

Answer 1

[Star Strider]

This works:

u=[1 1 1 1 1 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 0 0 0]
pctg_1 = sum(u)/size(u,2) * 100         % Percentage of ‘1’
pctg_0 = 100 - pctg_1                   % Percentage of ‘0’

produces:

pctg_1 =

      48.0000

pctg_0 =

      52.0000

[Bojan]

yes this is working thank you very much. But do you know how to get percentage of each value in 'transitions' vector...? Regards

[José-Luis]

That's a different question.

 doc histc

 [you_need_this and_this] = histc(your_data,unique(your_data))

After that calculating the percentages is trivial.

[Bojan]

I got this from this calculations...

[bincounts ind]=histc(transitions, unique(transitions))

bincounts =

     1     2     2     1

   ind =

     3     2     1     4     3     2

[José-Luis]

 your_values = unique(transitions);

bincounts tells you how many of your_values there are in transitions. Calculating a percentage after that is simple arithmetic:

 percentage = num_values / tot_values * 100;

[Star Strider]

This works:

transitions = [5     3     2     7     5     3]
trn_nrs = histc(transitions, 1:max(transitions))   % Do histogram of ‘transitions’
trn_pctg = trn_nrs/size(transitions,2)information  % Percentage of each transition
hist_trn_pctg = [trn_pctg; 1:max(transitions)]      % Percentages and values

The hist_trn_pctg array has the percentages in the first row and the values of the transitions in the second row:

hist_trn_pctg =

       0.0000   0.1667   0.3333     0.0000   0.3333     0.0000   0.1667
       1.0000   2.0000   3.0000     4.0000   5.0000     6.0000   7.0000

[Bojan]

THANK YOU VERY MUCH GUYS ! ! !

[Star Strider]

My pleasure!

[SRAVAN KUMAR REDDY METTUPALLI]

What if the input is [1 0 ; 0 1 ]

[rehan anwar]

It will not work when matrices is

[1 0;0 1]?????

explain.

[Image Analyst]

That's because he used size(u, 2) to count the number of column. This fix will make it work for any array, regardless of the shape/dimensions and regardless of what values are in there (0, 1, or other values):

percentageOfOnes = sum(u(:) == 1) / numel(u) * 100         % Percentage of ‘1’

[Walter Roberson]

The original Question asked specifically about vectors. For arrays,

pctg_1 = sum(u(:))/numels(u) * 100         % Percentage of ‘1’

Or,

pctg_1 = nnz(u)/numels(u) * 100         % Percentage of ‘1’

Or more simply,

pctg_1 = mean2(u) * 100         % Requires Image Processing Toolbox

Answer 2

[Vijayramanathan B.tech-EIE-118006077]

function a = zero_stat(b)

c=(sum(b(:))/numel(b))*100;

a=100-c;