Why is my last line coming up as an empty sym?

There's a couple steps to this problem. Expand and then simplify the equation. The last is to solve this equation: when x =2. But when I run it, it comes up empty

𝑦= (𝑥^3 +1)(𝑥^2 +2𝑥−5)(𝑥^2 −3)^2

clear

syms x

x==2

y = (x^3+1)*(x^2+2*x-5)*(x^2-3)^2 %deleted "eqn =' double = leads to error

expand(y) %switch out "eqn" with "y"

simplify(y) %same as above

solve(subs(y,x,2),y)

Answer 1

[Cris LaPierre]

I don't think you need to use solve in the final line. Substituting in 2 for x will return a value for y. There is nothing left to solve for.

syms x  
y = (x^3+1)*(x^2+2*x-5)*(x^2-3)^2 %deleted "eqn =' double = leads to error

y = 

subs(y,x,2)

ans = 

27

[Amy Joyce Valencia]

Thank you!