Drawing a hyperboloid with polar coordinates
3 views (last 30 days)
Show older comments
Szabolcs Simon-Guth
on 5 Nov 2021
Commented: Mathieu NOE
on 8 Nov 2021
Hi all!
I have received the following problem to solve:
Draw the surface of the hyperboloid with the equation:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790709/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790714/image.png)
Also, the polar coordinates for x and y must be used, i.e.:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790719/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790724/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790729/image.png)
I have converted the equation of the hyperboloid so that it became: ![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790734/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790734/image.png)
I could then express z as: ![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790739/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/790739/image.png)
I have the following code so far:
r = linspace(0,1,21);
a = linspace(0,2*pi,63);
[R,A] = meshgrid(r,a);
X = R.*cos(a);
Y = R.*sin(a);
Z = square((R.^2)-1);
surf(X,Y,Z);
axis equal
However, when ever I run the program I get a cylinder instead. I think the problem might be that the values of z should be between -3 and 3, however I do not know how to express this in the code. I would appricate any help that I get. Thank you for everyone in advance!
0 Comments
Accepted Answer
Mathieu NOE
on 5 Nov 2021
hello
you have to start from z and then compute r and not vice versa
also square root function is sqrt and not square
z = linspace(-3,3,21);
a = linspace(0,2*pi,63);
[Z,A] = meshgrid(z,a);
R = sqrt((Z.^2)+1);
X = R.*cos(A);
Y = R.*sin(A);
surf(X,Y,Z);
axis equal
2 Comments
More Answers (0)
See Also
Categories
Find more on Surface and Mesh Plots in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!