How to reduce matrix size conditionally?

Hi everyone,

My dataset consists of 194 rows and 5 column. in each row either a non-zero value or NaN. I require to pick the non-zero value (only one). There may be more than one non-zero values but all are same, so i need only one. As a resul the size of output matrix will be 194 by 1.

Thansk.

Answer 1

[Voss]

Here's one way:

N = max(N_total,[],2);

[Adnan Barkat]

Thanks

Answer 2

[Simon Chan]

Try this:

mean(N_total,2,'omitnan')

Answer 3

[Davide Masiello]

You could use the max function. See below

% here I reproduce your type of matrix
A = rand(194,1);
A = [A,A,A,A,A];
A(logical(randi([0,1],size(A)))) = nan

A = 194×5

NaN NaN NaN 0.2306 0.2306 NaN NaN NaN 0.2761 NaN NaN NaN NaN NaN 0.3897 NaN NaN 0.5264 0.5264 0.5264 0.4432 NaN NaN 0.4432 0.4432 0.6612 NaN 0.6612 0.6612 NaN NaN NaN 0.3336 NaN 0.3336 0.3968 NaN 0.3968 0.3968 0.3968 NaN 0.7869 0.7869 0.7869 NaN 0.4621 NaN NaN NaN 0.4621

% Here I perform the required task
A = max(A,[],2)

A = 194×1

0.2306 0.2761 0.3897 0.5264 0.4432 0.6612 0.3336 0.3968 0.7869 0.4621