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How do i delete red box?

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Ann Lee
Ann Lee on 1 Apr 2022
Commented: Star Strider on 1 Apr 2022
is there any solution to not showing that red box?
i tried type ; every last of sentences and i couldnt find..
function A=work5(x)
m=1;
fun =@(n) log(n)./(n.^2);
fun2 =cube=@(n)(factorial(n))/(n.^n);
y = 10:10:160;
for k = y
n=1:k;
a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
A(1,m)=a;
a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
A(2,m)=a;
a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
A(3,m)=a;
a=sum(fun(n));
A(4,m)=a;
a=sum(fun(n));
A(5,m)=a;
m=m+1;
end
fprintf('k-sum\t\t%-10s\t%-10s\t%-10s\t%-10s\t%-10s\n','series a)',' series b)',' series c)',' series d)',' series e)');
fprintf('%-d-sum\t\t%18.16f\t%18.16f\t%18.16f\t%18.16f\t%18.16f\n',[y; A]);
end

Accepted Answer

Star Strider
Star Strider on 1 Apr 2022
You forgot one semicolon.
That is the one following the function call itself:
A=work5(x);
Add it, and the problem should be resolved.
.
  2 Comments
Ann Lee
Ann Lee on 1 Apr 2022
thank you!!!!
Star Strider
Star Strider on 1 Apr 2022
As always, my pleasure!

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More Answers (1)

Voss
Voss on 1 Apr 2022
Put a semicolon at the end of the line where you call work5()
x = 0.5;
A=work5(x); % semicolon here to suppress output
k-sum series a) series b) series c) series d) series e) 10-sum 0.2360917042622818 0.0183477336900002 2.6037130567248910 0.6185026440390786 0.6185026440390786 20-sum 0.2360935069156409 0.0046901266642478 2.8014162630672139 0.7414543314498736 0.7414543314498736 30-sum 0.2360935069373981 0.0021024390062099 2.8760197072997613 0.7927133235796062 0.7927133235796062 40-sum 0.2360935069373984 0.0011879757954263 2.9152273498982542 0.8214707392666620 0.8214707392666620 50-sum 0.2360935069373983 0.0007624261816455 2.9394033796823531 0.8400856497460111 0.8400856497460111 60-sum 0.2360935069373983 0.0005304643434289 2.9558025281112354 0.8532083972941535 0.8532083972941535 70-sum 0.2360935069373983 0.0003902616907145 2.9676576344553687 0.8630014494171609 0.8630014494171609 80-sum 0.2360935069373983 0.0002991030456768 2.9766276503926639 0.8706140035662616 0.8706140035662616 90-sum 0.2360935069373983 0.0002365196042555 2.9836515597777193 0.8767161095759303 0.8767161095759303 100-sum 0.2360935069373983 0.0001917055505272 2.9893007392892499 0.8817261267819699 0.8817261267819699 110-sum 0.2360935069373983 0.0001585190387434 2.9939428224039832 0.8859194142887463 0.8859194142887463 120-sum 0.2360935069373983 0.0001332595661518 2.9978250830782560 0.8894849752852432 0.8894849752852432 130-sum 0.2360935069373983 0.0001135896806734 3.0011199661058376 0.8925570525004751 0.8925570525004751 140-sum 0.2360935069373983 0.0000979740413573 3.0039514025437972 0.8952337438272375 0.8952337438272375 150-sum 0.2360935069373983 0.0000853704311945 3.0064107493745813 0.8975884770604837 0.8975884770604837 160-sum 0.2360935069373983 0.0000750512206079 3.0085668320159584 0.8996773562961806 0.8996773562961806
function A=work5(x)
m=1;
fun =@(n) log(n)./(n.^2);
% fun2 =cube=@(n)(factorial(n))/(n.^n);
y = 10:10:160;
for k = y
n=1:k;
a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
A(1,m)=a;
a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
A(2,m)=a;
a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
A(3,m)=a;
a=sum(fun(n));
A(4,m)=a;
a=sum(fun(n));
A(5,m)=a;
m=m+1;
end
fprintf('k-sum\t\t%-10s\t%-10s\t%-10s\t%-10s\t%-10s\n','series a)',' series b)',' series c)',' series d)',' series e)');
fprintf('%-d-sum\t\t%18.16f\t%18.16f\t%18.16f\t%18.16f\t%18.16f\n',[y; A]);
end

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