trajectory of an electron in an electron beam evaporator
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I already made a code, but I want the path to be circular, please help
clc; clear all
M = 100 ;
t = linspace(0,20,M) ;
m=9.1e-31 ;
q=-1.6e-19 ;
P = zeros(M,3) ;
V = zeros(M,3) ;
p = rand(1,3) ;
v = rand(1,3) ;
P(1,:) = p ;
V(1,:) = v ;
c = rand ;
E=[0 0 c] ;
d = rand ;
B=[0 0 d] ;
for i = 2:M
f=q*E+q*cross(v,B) ;
a=f/m ;
v = v+a*t(i) ;
p = p+v*t(i) ;
P(i,:) = p ;
V(i,:) = v ;
end
plot3(P(:,1),P(:,2),P(:,3));
axis equal
xlabel('x'); ylabel('y'); zlabel('z');
grid on
set(gca,'fontsize',14);
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Answers (1)
Swapnil Tatiya
on 13 Jul 2023
The electron shall not go in a circle when both E field and B field are applied simultaneously,so I've modified your code such that there's just B field so that you get a trajectory as you desired.
M = 100;
t = linspace(0,20,M) ;
m=9.1e-31 ;
q=-1.6e-19 ;
P = zeros(length(t),3) ;
V = zeros(length(t),3) ;
V(1,:) = [0 rand(1) 0] ;
d = rand(1) ;
B=[0 0 10^-12] ;
for i = 2:length(t)
f=q.*(cross(V(i-1,:),B));
a=f/m;
V(i,:) = V(i-1,:)+a*(t(i)-t(i-1)) ;
P(i,:) = P(i-1,:)+V(i-1,:)*(t(i)-t(i-1)) ;
end
plot(P(:,1),P(:,2))
grid on
Hope this helps!
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