How to automatically open the files in this m-code

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hello. I couldn't solve the problem from last answers.. so I bring the m-code I wrote as below:
clear
clc
fileID = fopen('number_of_filename.txt','w');
fprintf(fileID,'%6s\n','number');
for ii=1:100
[file,path]=uigetfile('*.txt');
file_name=file
filename=fullfile(path,file);
fid = load(filename);
idx = find(file_name == ' ', 1, 'first');
part1 = file_name(1:idx-1);
fprintf(fileID,'%6s\n',part1);
end
fclose(fileID);
The name of the txt files are 0.5 f.txt, 1.0 f.txt, 1.1 f.txt, 3.0 f.txt, 5.6 f.txt, 10.0 f.txt ... and so on. The numbers are random.
Above code will give me the 'number part of the file name' only, which are 0.5, 1.0, 1.1, 3.0, 5.6, 10.0 ... and so on.
Here, I am to select txt files one by one, over and over. The problem is, I have over 1 thousand txt files....
How can I modify the above code to let the m-file run all 1 thousand txt files by itself?
  3 Comments
yc j
yc j on 26 Jan 2016
i can't... the file name means something and i need them...

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Answers (1)

Walter Roberson
Walter Roberson on 26 Jan 2016
  2 Comments
Stephen23
Stephen23 on 26 Jan 2016
Edited: Stephen23 on 26 Apr 2021
And then use my FEX submission natsortfiles to get the files into numeric order:
S = dir(...);
S = natsortfiles(S,'\d+\.?\d*');
for k = 1:numel(S)
S(k).name
...
end
Walter Roberson
Walter Roberson on 26 Jan 2016
It turns out in another Question that the names have a variable number of decimal places that sometimes include trailing 0 and sometimes do not.

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