Peak to average power ratio (PAPR)

      Hello,

Given a predefined PAPR (e.g. 10dB) and a signal, I want to generate  a noisy signal so that 
PAPR = 10*log10(PowerPeakAmplitude/PowerAverage):

This is what I've tried so far:

function noisy_signal = addNoiseToSignal(signal,papr)

% calculate the power of the peak amplitude peakPowerValue = max(signal.^2);

% signal length N = length(signal);

% calculate the average power of the noise noisepower = peakPowerValue /(10^(papr/10));

% generate noise noisesignal = randn(1,length(signal))*sqrt(noisepower);

% create noisy signal noisy_signal = signal + noisesignal;

The problem is that when I can't get a correct signal with the given noisepower.

Mar

[Yasir Ahmed]

PAPR=max((abs(x)).^2)/mean((abs(x)).^2)

[Pendukeni Phalaagae]

Thank you so much Yasir Ahmed,what does max((abs(x)).^2) present and mean((abs(x)).^2)?

Does mean((abs(x)). ^2) present avergage power and

max((abs(x)). ^2) present peak power