Looping matrice column by subtraction
2 views (last 30 days)
Show older comments
I have a 84x7 matrices. On the entire column 2 and 4, they need to be subtracted from higher number - lower and loop through the whole 84 rows and put them into a new 84x1 vector. How can this be done? let 4x4 matrix a = [x 3 2 y; x 4 1 y; x 1 6 y; x 2 7 y; x 5 1 y;
b= [3-2 4-1 6-1 7-2 5-1]
b= [1 3 5 5 4 ]
Accepted Answer
madhan ravi
on 21 Oct 2018
Edited: madhan ravi
on 21 Oct 2018
EDIT 2
a = randi([0 9],84,7) %fake data to test
a1=a(:,2) %column you want to extract
a2=a(:,5) %column you want to extract
a=[a1 a2] %two columns stored in a matrix , sorry I missed this line which caused the error
idx = find(a1<a2)
a(idx,:)=fliplr(a(idx,:))
b = a(:,1) - a(:,2) % as column vector
b1 = b' %row vector
12 Comments
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!