Changing the unknown variable in a matlab line

1 view (last 30 days)
I have the following line in matlab:
y=sum(bin(xout>xout(1) & xout < -lim));
In the above line, Iam computing the value 'y' from known row-vectors 'bin' , 'xout', and known value 'lim'
How can I write the above equation, if I want to compute the value 'lim' if the value 'y' and row-vectors 'bin', 'xout' are now known.
%%---- Following scenario ---%% PICTURE ADDED
Please help
  6 Comments
Azzi Abdelmalek
Azzi Abdelmalek on 16 Aug 2012
do you mean bin(1x6000) and xout(1x200)? because with bin(1x200) and xout(1x6000).
y=sum(bin(xout>xout(1) & xout < -lim));
don't work

Sign in to comment.

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 16 Aug 2012
Edited: Azzi Abdelmalek on 16 Aug 2012
Example: run this to find y
bin=rand(20,1);xout=rand(20,1);lim=-0.5;
y=sum(bin(xout>xout(1) & xout < -lim));
then run this to find lim
lim=[];
for k=1:length(xout);
if sum(bin(xout>xout(1) & xout < xout(k)))==y;
lim=[lim -xout(k)]
end
end
lim=max(lim)
note: you will notice that lim is not exactly the same as the first. and if lim contains many values, you choose the bigest (-lim will be the smaller)
  3 Comments
Azzi Abdelmalek
Azzi Abdelmalek on 16 Aug 2012
Edited: Azzi Abdelmalek on 16 Aug 2012
if y is given by
y=sum(bin(xout>xout(1) & xout < -lim));
lim can't be empty, unless you impose y. in this case, it's possible that lim will be empty
zozo
zozo on 16 Aug 2012
I changed:
if sum(bin(xout>xout(1) & xout < xout(k)))==y;
to
if sum(bin(xout>xout(1) & xout < xout(k)))<=y;
and now it works! Thanks Azzi

Sign in to comment.

More Answers (1)

Image Analyst
Image Analyst on 16 Aug 2012
How about (untested)
% Get area as function of xout.
cumulativeSum = cumsum(bin);
% For a given area, called desiredArea,
% find the index where the cumulative sum first exceeds that area.
lim = find(cumulativeSum >= desiredArea, 1, 'first');
% lim was the index. Now find the xout value at that index:
xOutValue = xout(lim);

Categories

Find more on Cell Arrays in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!