could anyone help me to solve the issue.

code:
A=partitions(4)
partdisp(A)

where partitions and partdisp are functions

when i run the above code it executes and gives the following result

The formation of clusters {1 2 3 4}:

{1 2 3 4} 
{1 2 3} {4} 
{1 2 4} {3} 
{1 2} {3 4} 
{1 2} {3} {4} 
{1 3 4} {2} 
{1 3} {2 4} 
{1 3} {2} {4} 
{1 4} {2 3} 
{1} {2 3 4} 
{1} {2 3} {4} 
{1 4} {2} {3} 
{1} {2 4} {3} 
{1} {2} {3 4} 
{1} {2} {3} {4} 

with respect to the result i need to avoid the formation which contains {2 3},{2,4},{3,4}.

Could anyone please help me on it.

[Walter Roberson]

This appears to relate to https://www.mathworks.com/matlabcentral/fileexchange/24185-partitions

[Walter Roberson]

You would get a lot further on your project if you stopped trying to find clever ways to accomplish tasks, and just resorted to using loops and if statements.

For any kind of project like yours, the most important part is to get the code to work (correctly). You can worry about making it work faster or "more matlab-like" once it works.

[jaah navi]

yes.I got it form the link.

but I dont want to display all the formation.

I need to remove the formation which contains {2,3},{3,4},{2,4}.

could you please help me how to remove it.

[Walter Roberson]

Remove the entries of A that would meet those conditions before you do the partdisp()

The partitions code returns a cell array row vector (one column). Each row is a cell array with possibly multiple entries. So for example for row K, A{K} would be a cell array whose entries are each a subset.

Given one particular partitioning expressed as a cell array, how would you test whether it has an entry which is {2,3}, {2,4}, or {3,4} ?