Plotting Multivariable x, y, and z for a data set

29 views (last 30 days)
I have made a 3d multivatiable gird that is, x, y, and z
grid_x = 1:1:10;
grid_y = 1:1:10;
grid_z = 1:1:10;
then in a 3 loop (3d multivariable) I calculate values for a give equation and save is it in a variable called values(:,:). the multivariable values has points between 1:10 random numbers
Now I have used
[X,Y] = meshgrid(grid_x,grid_y);
Z = griddata(grid_x,grid_y,grid_z,X,Y);
however Z is not where the values are, when I call
I get a empty plot in 3d, here is where I am not understand how to call in the data points which is called values, even when I did
I get a empty plot in 3d.
Please tell me to clarify if needed.

Accepted Answer

Star Strider
Star Strider on 5 Oct 2020
The problem is with your choice of coordinates.
When I ran your code, it threw:
Warning: The underlying triangulation is empty - the points may be collinear.
> In griddata>useScatteredInterp (line 183)
and ‘Z’ was empty.
Creating random values instead resulted in the sort of result you want:
grid_x = rand(1,50);
grid_y = rand(1,50);
grid_z = randn(size(grid_x));
[X,Y] = meshgrid(0:0.01:1, 0:0.01:1);
Z = griddata(grid_x,grid_y,grid_z,X,Y);
grid on
SugerCodeCude on 6 Oct 2020
Thank you so mch, this back and forth help me understand the issues I was having. Thank you again!

Sign in to comment.

More Answers (0)


Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!