# Is there a matrix which can be alphanumeric?

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Jay Vaidya on 11 Nov 2020
Answered: Cris LaPierre on 11 Nov 2020
I am trying to make a matrix like
1n -1
1n 2
1n 1
1n 3
The first column is going to be concatenated string where the first alphabet is the counter of the for loop and the alphabet 'n'
For ex: for coun = 1:1:10
code will go here
end
should give output for coun = 3 as:
3n
3n
3n
3n
and then I need to put this along with a new matrix j which is
-1
2
1
3
The order of the final matrix is decided by the matrix j as it has the same number of rows as the number of rows of the matrix j.
So the final output is:
3n -1
3n 2
3n 1
3n 3

Cris LaPierre on 11 Nov 2020
A matrix cannot contain mixed data types. It's possible to create a string array that does what you want, but everything will have to be strings.
a = string(ones(4,1)*3)+"n";
b = [-1 2 1 3]';
j=[a string(b)]
j = 4×2 string array
"3n" "-1" "3n" "2" "3n" "1" "3n" "3"
If instead you want to mix data types, you could use a table.
j=table(a,b)
j = 4x2 table
a b ____ __ "3n" -1 "3n" 2 "3n" 1 "3n" 3

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