compare 2 matrix with different dimensions
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Hi, assume that I have a matrix 'info' (800,3), the first column is for ID, the second column is for coordinate x and the last column is for coordinate y. Additionally I have a matrix called 'coordinates'(200,2) where the first column is coordinate x and the second is coordinate y. I want to compare this matrix with the 'info' matrix to find the IDs where the matrix 'coordinates' is equal to the 'info' matrix.
Thanks
Accepted Answer
Walter Roberson
on 10 Jun 2013
[tf, idx] = ismember( info(:,2:3), coordinates, 'rows');
match_IDs = info(tf, 1);
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More Answers (1)
Azzi Abdelmalek
on 10 Jun 2013
Edited: Azzi Abdelmalek
on 10 Jun 2013
A=[1 10 20;2 100 200;3 1000 2000;4 44 55]
B=[11 20;100 200;1 4;44 55 ]
out=A(~any(A(:,2:3)-B,2),1)
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Walter Roberson
on 11 Jun 2013
any() by default works along the first dimension (so down columns), but it accepts an optional dimension number. dimension #2 means across rows.
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