Answered

how can i solve this problem with rk4 method?

If m=20, k=20, c=40 then function f should be f = -(c/m)*v - k/m f=@(t,x,v) -2*v -x; %dvdt

how can i solve this problem with rk4 method?

If m=20, k=20, c=40 then function f should be f = -(c/m)*v - k/m f=@(t,x,v) -2*v -x; %dvdt

14 hours ago | 0

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Answered

How to solve a function with different ranges

Try C_ox = [16;15;7.5;2;7.5;15;15]; C_ox(C_ox<=15)=C_ox(C_ox<=15)/15; C_ox(C_ox>15)=1

How to solve a function with different ranges

Try C_ox = [16;15;7.5;2;7.5;15;15]; C_ox(C_ox<=15)=C_ox(C_ox<=15)/15; C_ox(C_ox>15)=1

1 day ago | 0

Answered

how can i solve second order ODE with RK-4 without using a built in function in matlab?

This K11 = RK4(t(i), y1(:, i)); should be | K11 = RK4(t(i), y(:, i)); and this f12 = -3*y(1)+30*t+10; ...

how can i solve second order ODE with RK-4 without using a built in function in matlab?

This K11 = RK4(t(i), y1(:, i)); should be | K11 = RK4(t(i), y(:, i)); and this f12 = -3*y(1)+30*t+10; ...

2 days ago | 0

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Answered

How to design the membership function in matlab?

How about the following for rule 3 (I'll leave you to invert for rule 4). x = [-180 -90 -89.001 89.001 90 180]; y = (x+180)/90...

How to design the membership function in matlab?

How about the following for rule 3 (I'll leave you to invert for rule 4). x = [-180 -90 -89.001 89.001 90 180]; y = (x+180)/90...

5 days ago | 0

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Answered

Help for plotting graph. Can someone help me?

In your while loop you don't update either nErrorsBitsW or nErrorsBitsInf so they always stay at 0, and never reach minNbits.

Help for plotting graph. Can someone help me?

In your while loop you don't update either nErrorsBitsW or nErrorsBitsInf so they always stay at 0, and never reach minNbits.

6 days ago | 0

Answered

how I can insert these specific colours into my figures

Do you mean something like this? newcolors = [0 0.4470 0.7410; 0.8500 0.3250 0.0980; 0.9290 0.6940 0.1250...

how I can insert these specific colours into my figures

Do you mean something like this? newcolors = [0 0.4470 0.7410; 0.8500 0.3250 0.0980; 0.9290 0.6940 0.1250...

7 days ago | 1

Answered

Transpose x from a row vector to a column vector using the transpose operator. The program is prompting the x does not have correct values. the code i have entered is below

You probably meant x = [1:5]; % ie the ; is after the ] However, it seems to work ok for me as you wrote it!

Transpose x from a row vector to a column vector using the transpose operator. The program is prompting the x does not have correct values. the code i have entered is below

You probably meant x = [1:5]; % ie the ; is after the ] However, it seems to work ok for me as you wrote it!

7 days ago | 0

Answered

Replace a entry of a table of Bisection Method for a specific term

Try using NaN or [ ];

Replace a entry of a table of Bisection Method for a specific term

Try using NaN or [ ];

8 days ago | 0

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Answered

Plotting the intersection of a composition function

Do you mean something like this? Sfn = @(x) (x+1/4).*(x<=1/2) + (x+3/4).*(x>1/2); x = linspace(0,1,100); n=10; S = zeros(n,n...

Plotting the intersection of a composition function

Do you mean something like this? Sfn = @(x) (x+1/4).*(x<=1/2) + (x+3/4).*(x>1/2); x = linspace(0,1,100); n=10; S = zeros(n,n...

18 days ago | 0

Answered

Sun Synchronous with For Loop

When I run the program you've listed above it produces the graph you show!

Sun Synchronous with For Loop

When I run the program you've listed above it produces the graph you show!

18 days ago | 0

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Answered

Integration of a function with variable parameter

Do you mean something like this? H = @(tau, lam, tt) lam./exp(tt-tau); T=50; step=1000; h=T/step; t=0:h:T; lambda = rand(1...

Integration of a function with variable parameter

Do you mean something like this? H = @(tau, lam, tt) lam./exp(tt-tau); T=50; step=1000; h=T/step; t=0:h:T; lambda = rand(1...

19 days ago | 0

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Answered

How to get sinusodial behaviour from 2nd order ode using function handle?

You coud try implementing the function along these lines (obviously, you will need to use your own values for alpha etc): alpha...

How to get sinusodial behaviour from 2nd order ode using function handle?

You coud try implementing the function along these lines (obviously, you will need to use your own values for alpha etc): alpha...

20 days ago | 0

Answered

How to find absolute maximum value of (x*(x-.25)*(x-.5)*(x-1))

You could just do something like gx = @(x) ((x.^4) -(1.75*x.^3)+(0.875*x.^2)-(0.125*x)); X = roots([4, -5.25, 1.75, -0.125]); ...

How to find absolute maximum value of (x*(x-.25)*(x-.5)*(x-1))

You could just do something like gx = @(x) ((x.^4) -(1.75*x.^3)+(0.875*x.^2)-(0.125*x)); X = roots([4, -5.25, 1.75, -0.125]); ...

21 days ago | 0

Answered

I want to see N,M first and then K,M in the same legend. I can see only N,M like the attached picture.

Do you mean like this? N = [10 20 30 40 50]; M = [1 2 3 4 5]; K=[1 3 5 6 7]; x = linspace(0, 1, 17); legendString = "N = " ...

I want to see N,M first and then K,M in the same legend. I can see only N,M like the attached picture.

Do you mean like this? N = [10 20 30 40 50]; M = [1 2 3 4 5]; K=[1 3 5 6 7]; x = linspace(0, 1, 17); legendString = "N = " ...

21 days ago | 0

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Answered

How to take integral with for loop?

Add the command I = sum(final); after the loop.

How to take integral with for loop?

Add the command I = sum(final); after the loop.

23 days ago | 0

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Answered

Solving queue problem iterating through array

Try Lock19(Lock19~=-5)=0; Lock19(Lock19==-5)=3;

Solving queue problem iterating through array

Try Lock19(Lock19~=-5)=0; Lock19(Lock19==-5)=3;

23 days ago | 0

Answered

Sum of even numbers

Like so s = test(6); disp(s) function s = test(n) if n <= 0 %for n<= 0 the result would be 0 s = 0; els...

Sum of even numbers

Like so s = test(6); disp(s) function s = test(n) if n <= 0 %for n<= 0 the result would be 0 s = 0; els...

29 days ago | 0

Answered

Stopping ode45 when encountering errors and retrieving results

The following makes your example work. However, I suspect your real problem is more complicated. If so, you should upload it. ...

Stopping ode45 when encountering errors and retrieving results

The following makes your example work. However, I suspect your real problem is more complicated. If so, you should upload it. ...

29 days ago | 0

Answered

After comma precision tracking for if statement

Here's one possibility a=85.0093792283283; b=85.0093791964294; a = floor(a*10^3); b = floor(b*10^3); if a==b disp('n...

After comma precision tracking for if statement

Here's one possibility a=85.0093792283283; b=85.0093791964294; a = floor(a*10^3); b = floor(b*10^3); if a==b disp('n...

29 days ago | 0

Answered

help me solve this if statement

Remove the ] in the top line! Then number = randi([0,9]) evens = [2,4,6,8]; odds = [1,3,5,7,9]; if ismember(number,evens) ...

help me solve this if statement

Remove the ] in the top line! Then number = randi([0,9]) evens = [2,4,6,8]; odds = [1,3,5,7,9]; if ismember(number,evens) ...

29 days ago | 0

Answered

Error: ode45 Must return a column vector?

Like this? % the total time domain response % System parameters k3 = 15; k1 = 10.0; k2 = 10.0; m1 = 2.0; m2 = 6.0; L = 1.0;...

Error: ode45 Must return a column vector?

Like this? % the total time domain response % System parameters k3 = 15; k1 = 10.0; k2 = 10.0; m1 = 2.0; m2 = 6.0; L = 1.0;...

1 month ago | 1

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Answered

How to solve following BVP ODE?

Weird ODE and initial boundary condition! You can solve for small values of x using the following (where y(x=0) was chosen by t...

How to solve following BVP ODE?

Weird ODE and initial boundary condition! You can solve for small values of x using the following (where y(x=0) was chosen by t...

1 month ago | 1

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Answered

Array indexes must be positive integers or logical values.

Looks like you are using SUM when you want sum. Change to: SUM= E1*sum(V(3:IOUT+1,JOUT+2)).... Also, in line 59, you should h...

Array indexes must be positive integers or logical values.

Looks like you are using SUM when you want sum. Change to: SUM= E1*sum(V(3:IOUT+1,JOUT+2)).... Also, in line 59, you should h...

1 month ago | 1

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Answered

How to get real solutions of a "system of nonlinear equations"?

If you are willing to do the differentiation by hand then the following works % L = 2*x^2 -2*x*y+y^3 + lambda*(x^2 + y^2 -4); ...

How to get real solutions of a "system of nonlinear equations"?

If you are willing to do the differentiation by hand then the following works % L = 2*x^2 -2*x*y+y^3 + lambda*(x^2 + y^2 -4); ...

1 month ago | 0

Answered

Calling Euler Method to solve Shooting Method

You need to express your 2nd order ode as two 1st order odes y``(x) + 5y`(x) + 4y(x) = 1 v = dy/dx dv/dx = y``(x) So you h...

Calling Euler Method to solve Shooting Method

You need to express your 2nd order ode as two 1st order odes y``(x) + 5y`(x) + 4y(x) = 1 v = dy/dx dv/dx = y``(x) So you h...

1 month ago | 0

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Answered

solving Diffrential equation one parameter related to another one

Like this? %% Input Parameters Rs = 200; Rr = 180; Phi = 180; t = 0:1:359; e = Rs - Rr; %% Calculation B = @(t) e*co...

solving Diffrential equation one parameter related to another one

Like this? %% Input Parameters Rs = 200; Rr = 180; Phi = 180; t = 0:1:359; e = Rs - Rr; %% Calculation B = @(t) e*co...

1 month ago | 0

Answered

error handling for complex equation

nchoosek(pc-1+iL,pc-1-k) Your value of pc-1-k isn't a non-negative integer, but it needs to be for nchoosk. Also why use s...

error handling for complex equation

nchoosek(pc-1+iL,pc-1-k) Your value of pc-1-k isn't a non-negative integer, but it needs to be for nchoosk. Also why use s...

1 month ago | 0

Answered

merging two ode graphs

Your testode2 function must return a column vector. Try function dy = testode2(~,y) %%% Must return a column vector j=1;bet...

merging two ode graphs

Your testode2 function must return a column vector. Try function dy = testode2(~,y) %%% Must return a column vector j=1;bet...

1 month ago | 0

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Answered

Simulation of differential equations with multiple variables. Biotechnology

You set umax to be 0.33, but then treat it as a function in the definition of f. If umax should simply be multiplied by the oth...

Simulation of differential equations with multiple variables. Biotechnology

You set umax to be 0.33, but then treat it as a function in the definition of f. If umax should simply be multiplied by the oth...

1 month ago | 0

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