# Error using cos Not enough input arguments. HELP

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Kayn on 6 Nov 2013
Commented: Walter Roberson on 29 Jun 2021
Hi all,
Can anyone help me with this problem - Error using cos Not enough input arguments.
x=0:0.25:5.*pi;
y=0:0.25:2.*pi;
[x,y]=meshgrid(x,y);
z = cos.*((x).*sin(y)).*((1-3.*cos((y).^2))-(x.^2).*sin((y).^2)).*cos(x);
Error using cos Not enough input arguments.
I'm new to MatLab and I need to plot a contour map using this function but I can't seem to find a way to get rid of the error message. Any help would be much appreciated.
Thanks, Kayn.

Azzi Abdelmalek on 6 Nov 2013
Edited: Azzi Abdelmalek on 6 Nov 2013
You missed something in cos.* ,maybe you want
z = cos(x).*((x).*sin(y)).*((1-3.*cos((y).^2))-(x.^2).*sin((y).^2)).*cos(x);
You missed something in cos.
Azzi Abdelmalek on 6 Nov 2013
cos(x.*sin(y))
Kayn on 6 Nov 2013
Yes, this works! Many, many thanks Azzi. I now have my contour maps and am trying to make them look nice. Thanks again.

Diego David Tubay Lozano on 6 Mar 2021
diff(sin^2*([cos^2*(x^2)]))
Error using sin
Not enough input arguments.
help.
Walter Roberson on 6 Mar 2021
syms x
diff(sin(x)^2 * cos(x^2)^2, x)
ans =
or possibly you meant
syms x
diff(sin(cos(x^2)^2)^2, x)
ans =

5*cos(x)+4.2501-cos*(0.52367-x)
Error using cos
Not enough input arguments.
Error in Secant2 (line 13)
Walter Roberson on 29 Jun 2021
You have a function named Secant2 that takes at least one parameter, that is named x in the function.
When you ran the function Secant2 you did not provide any parameters at the time of the call. You probably just pressed the big green Run button. When you press the green Run button, MATLAB will run the function without providing any parameters. If you run a function that has a variable (such as x) defined as a parameter, but you run the function without providing a value in that position, then MATLAB will never go hunting around elsewhere looking for an "x" defined somewhere to use as the value in the function. For example,
x = pi/7
y = sin
if sin were defined like
function sx = sin(x)
then MATLAB will never go looking in the workspace to find the pi/7 value to use for the function. If you want a function to use a parameter, then you have to pass the parameter to it.