Generating integer random numbers from power-law distribution

Is there a code to generate integer random numbers through power-law distribution of the form p(x)=x^-(alpha+1)?
thanks in advance

More Answers (3)

I don't know if round,ceil or floor is correct, but in case this may be a way
n=1000;
p=rand(1,n);
alpha=0.1;
%inverse of distribution
%properties of logs %LOGa(n) = LOGb(N) / LOGb(a)
%~round/ceil/floor
x=round(log(p)/log(alpha+1));

1 Comment

Thank you for your reply. Unfortunately, I cannot simply round or floor or ceil. I need to generate real integers.

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The distribution you mention is equivalent to the zeta distribution with alpha+1 replaced by s. See the website
http://en.wikipedia.org/wiki/Zeta_distribution
As Image Analyst has mentioned, there is a File Exchange contribution called 'randraw' which is located at:
http://www.mathworks.com/matlabcentral/fileexchange/7309-randraw
which claims to generate random numbers in accordance with fifty various distributions including the zeta distribution. It might be what you need.
I also meet the same problem. The minimum integer that zeta distribution can generate seems to be 1, but I hope 0 can be generated. Is there any other distributin can do this? Thank you

Asked:

on 13 Dec 2013

Answered:

on 18 Sep 2019

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