one line form of the follwing code

catchFolders = {'iptCatch','imtCatch','iftCatch','','junk','iitCatch'}; t = strfind(catchFolders(:),'Catch'); for k = length(t):-1:1 if isempty(t{k}), catchFolders(k)=[]; end end catchFolders

[Image Analyst]

What is your question? I mean, other than "how do I format my code so that it doesn't all show up on one line?" which will be solved once you read this: http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup

[Anuj Anand]

Sorry. My question was to remove the for-loop from the above code. Jos answered it beautifully. many thanks again

if true
  % code
catchFolders= {'iptCatch','imtCatch','iftCatch','','junk','iitCatch'}; 
t= strfind(catchFolders(:),'Catch'); 
for k= length(t):-1:1 
 if isempty(t{k}), 
   catchFolders(k)=[]; 
 end 
end 

end

Answer 1

[Jos (10584)]

You want a one-liner? Try these:

catchFolders = {'iptCatch','imtCatch','iftCatch','','junk','iitCatch'}  % data

catchFolders1 = catchFolders(~cellfun('isempty',strfind(catchFolders(:),'Catch'))) 
catchFolders2 = regexp(sprintf('%s ',catchFolders{:}),'\w*Catch\w*','match')

[Anuj Anand]

Many Thanks. This is brillient... the 2nd version is 7 times faster than the 1st version. Cheers.

[Jos (10584)]

You're welcome. But not that the second version is also a little more problematic than the first.

1. more difficult to understand
2. more prone to errors (especially when cells in catchFolders contain blanks)
3. not so easy to modify (e.g. when the string to search for is variable)

[Anuj Anand]

Thanks Jos, I did reaslise that. I did read up on it a little bit. Thanks again...