How to find real and complex roots for a nonlinear equation

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Marco Dellacasa
Marco Dellacasa on 21 Sep 2021
Commented: Marco Dellacasa on 22 Sep 2021
Hi everyone,
I have to solve this eqution numerically:
the only variable is H and it tipically gives two complex roots and one real root, I've read that fzero is not suitable in this case, could anyone give mi any tips please?
Thank you

Answers (1)

Viranch Patel
Viranch Patel on 22 Sep 2021
For simplicity I have taken a simple function which has complex roots.
syms H
eq=H^2 + 1;
solve(eq==0,H)
You can specify your equation in H like this and this should give you the roots correctly.
  1 Comment
Marco Dellacasa
Marco Dellacasa on 22 Sep 2021
Warning: Unable to solve symbolically. Returning a numeric solution using vpasolve.
> In sym/solve (line 304)
In prova_Irvine (line 15)
ans =
-8530666.6665264117623777679822889
>>
Unfortunately it didn't work, I know a priori that usually this equation has in total 3 roots: 2 complex and 1 real, maybe the problem is that I have both real and complex roots to find instead only real or only complex roots?

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