Count instances of subarray inside array

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Mitsu on 4 Nov 2021
Edited: Turlough Hughes on 7 Nov 2021
For an array
A = [2,2,2,2];
I would like to count how many times [2,2] appears in A, using each value only in one possible pair.
For example,
returns 3.
But if each "2" is used only once, then we have only 2 instances, instead of 3.
A is not necessarily of all same elements or even-number size, it could be e.g. A = [1,2,3].
Is there a simple way to do that?
Mitsu on 4 Nov 2021
I mean for this approach to work regardless of the size and elements, such as A = [1,2,3]. I edited the question to clarify.

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Answers (1)

Turlough Hughes
Turlough Hughes on 4 Nov 2021
You could do the following:
b = A == 2; % binary indicating where A equal to 2
count = 0;
ii = 1;
while ii < numel(A)
if b(ii+1) && b(ii)
count = count + 1;
ii = ii + 1;
ii = ii + 1;
When there is a match, the loop variable, ii, increments an extra time so that each "2" is only used once.
Turlough Hughes
Turlough Hughes on 4 Nov 2021
Another way would be to get the length of each group of twos (based on this answer by @Image Analyst) and then round down each group's length to the nearest whole number divisible by two:
measurements = regionprops(A == 2, 'Area');
allLengths = [measurements.Area];
count = sum(floor(allLengths/2))
(if you have the image processing toolbox)

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