How can I interpolate time?
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    Jaime De La Mota Sanchis
 on 8 Nov 2021
  
    
    
    
    
    Commented: Star Strider
      
      
 on 9 Nov 2021
            Hello everyone. 
I have a vector with times called 
tim1_1
, of size 51*1, I also have measurements called 
lam1_1
 made at those times. 
tim1_1
 goes between 0 and 1.737857815507103e+03. Instead of 51 measurements I want to have an arbitrary number, let's say 200. I have tried to write
interpLam1_1R = interp1(tim1_1,lam1_1,1:tim1_1(end)/200:tim1_1(end),'spline');
Unfortunately, if I plot the obtained results, they don't look like the original ones at all. As can be seen in the attached figure, the original data (in blue) looks almost sinusoidal,meanwhile, the interpolated data looks almost as a straight line. 
Can someone please help me with this problem?

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Accepted Answer
  Star Strider
      
      
 on 8 Nov 2021
        Apparently ‘tim1_1’ is not a datetime array.  
tim1_1 = linspace(0, 1.737857815507103e+03, 51);
lam_1 = sin(2*pi*1E-3*tim1_1);
tim1_2 = linspace(min(tim1_1), max(tim1_1), 200);
lam_1_2 = interp1(tim1_1, lam_1, tim1_2);
figure
plot(tim1_1, lam_1, '.b')
hold on
plot(tim1_2, lam_1_2, '.r')
hold off
grid
legend('Original','Interpolated', 'Location','best')
Experiment to get different results.  
.
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