dection of a word inside a condition (if)

I have programmed a code and I would like Matlab to recognise the word of materials (steel and aluminium). Any idea?

Following I put the code:

function y=kfgraf(r,Sut,material)

      a=xlsread('kf.xls'); %Extret del webplotdigitizer
      x1=a(1:67,1);
      y1=a(1:67,2);
      x2=a(1:65,3);
      y2=a(1:65,4);
      x3=a(1:64,5);
      y3=a(1:64,6);
      x4=a(1:63,7);
      y4=a(1:63,8);
      x5=a(1:59,9);
      y5=a(1:59,10);

      if material==steel && Sut<=0.4

          i1=interp1(x1,y1,r,'spline');
          y=i1
      end

      if material==steel && Sut>0.4 && Sut<=0.7

          i1=interp1(x1,y1,r,'spline');
          i2=interp1(x2,y2,r,'spline');

          prop=((Sut-0.4)/(0.7-0.4))
          y=i1+prop.*(i2-i1);
      end

      if material==steel && Sut>0.7 && Sut<=1

          i1=interp1(x2,y2,r,'spline');
          i2=interp1(x3,y3,r,'spline');

          prop=((Sut-0.7)/(1-0.7))
          y=i1+prop.*(i2-i1);
      end

      if material==steel && Sut>1 && Sut<=1.4

          i1=interp1(x3,y3,r,'spline');
          i2=interp1(x4,y4,r,'spline');

          prop=((Sut-1)/(1.4-1))
          y=i1+prop.*(i2-i1);
      end

      if material==steel && Sut>=1.4

          i1=interp1(x4,y4,r,'spline');
          y=i1
      end

      if material==aluminium

          i1=interp1(x5,y5,r,'spline');
          y=i1
      end
  end

Answer 1

[per isakson]

First idea:

    >> material = 'steel';
    >> strcmp( material, 'steel' )
    ans =
         1

[Josep]

What does this part of code do? Where should I put it?

[Image Analyst]

if strcmp(material, 'steel') && Sut>0.4 && Sut<=0.7

and so on.

[Josep]

I am doing this and I have an error message:

function y=kfgraf(r,Sut,material)

material='steel';
strcmp( material,'steel')

a=xlsread('kf.xls'); %Extret del webplotdigitizer
x1=a(1:67,1);
y1=a(1:67,2);
x2=a(1:65,3);
y2=a(1:65,4);
x3=a(1:64,5);
y3=a(1:64,6);
x4=a(1:63,7);
y4=a(1:63,8);
x5=a(1:59,9);
y5=a(1:59,10);

if strcmp( material,'steel') && Sut<=0.4 

      i1=interp1(x1,y1,r,'spline');
      y=i1;
  end

if strcmp( material,'steel') && Sut>0.4 && Sut<=0.7

      i1=interp1(x1,y1,r,'spline');
      i2=interp1(x2,y2,r,'spline');

      prop=((Sut-0.4)/(0.7-0.4));
      y=i1+prop.*(i2-i1);

end

if strcmp( material,'steel') && Sut>0.7 && Sut<=1

      i1=interp1(x2,y2,r,'spline');
      i2=interp1(x3,y3,r,'spline');

      prop=((Sut-0.7)/(1-0.7));
      y=i1+prop.*(i2-i1);

end

if strcmp( material,'steel') && Sut>1 && Sut<=1.4

      i1=interp1(x3,y3,r,'spline');
      i2=interp1(x4,y4,r,'spline');

      prop=((Sut-1)/(1.4-1));
      y=i1+prop.*(i2-i1);

end

if strcmp( material,'steel') && Sut>=1.4

      i1=interp1(x4,y4,r,'spline');
      y=i1

end

end

[per isakson]

"an error message" &nbsp What does it say and which line causes the error?

[Josep]

[Image Analyst]

How are you calling this function? It requires input arguments so you can't just click the green triangle to run it. What the warning (not error) is saying is that you accept material via the input argument list but you don't use it because you overwrite it immediately with the line

material='steel';

so whatever you pass in is ignored completely, so you might as well not bother having it or passing it in.