How can I make randi() in a loop not choose the same number
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Tariq Hammoudeh
on 8 Jan 2022
Answered: Walter Roberson
on 8 Jan 2022
I have an array
x=zeros(1,36)
then i have inside a while loop:
while ....
y=randi(length(x));
z=randi(length(x));
How can i make it so that this doesnt choose the same number at all,
Note: the loop will end before it gets to 36 choices, so its not that it doesnt have a choice but to go over the same numbers again
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Accepted Answer
Walter Roberson
on 8 Jan 2022
That would be a bit difficult. You would have to find a random number seed that you could set such that randi(36) happens to produce a permutation of the numbers 1 : 36. It could take a fair bit of work to find such a seed.
I would suggest that you take a completely different approach:
rand_y = randperm(length(x));
rand_z = randperm(length(x));
for K = 1 : length(x)
y = rand_y(K);
z = rand_z(K);
stuff
if some conditon;
break;
end
end
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