Error in using eval statement

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Ramesh Bala
Ramesh Bala on 10 Jan 2022
Edited: Stephen23 on 10 Jan 2022
Why it shows an incomplete statement ?
I'm trying to write this statement using eval as follows : Energy_H_A1S1 = rms (H_A1S1); but in eval it shows error ?
Thanks in advance.
eval(['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1);]);
  2 Comments
Ramesh Bala
Ramesh Bala on 10 Jan 2022
Thank you Stephen for your valuable reply.Yes that's right using names was wrong as it was indeed slow.

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Accepted Answer

Paul
Paul on 10 Jan 2022
There's almost certainly a better way to organize the data and store the results, but if you must use eval:
['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1);]
ans = 'Energy_H_A1S1 = rms(H_A1S1'
should be:
['Energy_H_A',num2str(1),'S',num2str(1),' = rms(H_A',num2str(1),'S',num2str(1),');']
ans = 'Energy_H_A1S1 = rms(H_A1S1);'
  4 Comments
Stephen23
Stephen23 on 10 Jan 2022
"Could you please also post an example of the mentioned better way instead of eval as it takes high running time for this varying A1..4..S1..4 data"
The MATLAB introductory tutorials also show how to use MATLAB effectively by using arrays and indexing:

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More Answers (1)

Walter Roberson
Walter Roberson on 10 Jan 2022
Asking how to use eval without problems is like asking how to use a chainsaw without its chain guard. It would be irresponsible for us to answer in any way other than "Don't do that!"
  1 Comment
Ramesh Bala
Ramesh Bala on 10 Jan 2022
Thank you Walter ,Indeed Eval was causing slowness when runnign the code.Thank you for the link

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